Molarity = moles of solute/volume of solution in liters.
There are 2.66 moles of KOH, the solute, and the volume of the solution is 0.750 L.
The molarity of this solution would thus be (2.66 moles KOH)/(0.750 L) = 3.55 M KOH.
Half of the land sides to the right and the other too the left.
It’s “a”, frequency because the sound waves will cause vibrations in object close by
Answer:
1 - e, 2 - k, 3 - a, 4 - i, 5 - b,
Explanation:
The ratio of the amount of analyte in the stationary phase to the amount in the mobile phase. --- Retention factor.
Time it takes after sample injection into the column for the analyte peak to appear as it exits the column. -- Retention time
The process of extracting a component that is adsorbed to a given material by use of an appropriate solvent system. -- Elution
Measure of chromatographic column efficiency. The greater its value, the more efficient the column. -- Theoretical plate number
Gas, liquid, or supercritical fluid used to transport the sample in chromatographic separations. -- Mobile phase
Immiscible and immobile, it is packed within a column or coated on a solid surface. -- Stationary phase
Answer:
d. 12.3 grams of Al2O3
Explanation:
The balanced chemical equation of this chemical reaction is as follows:
4Al + 3O2 --> 2Al2O3
Based on the balanced equation, 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).
First, we need to convert the mass of aluminum to moles using the formula;
mole = mass/molar mass
Molar mass of Al = 27g/mol
mole = 6.50/27
= 0.241mol of Al.
Hence, if 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).
Then, 0.241mol of Al will produce (0.241 × 2/4) = 0.241/2 = 0.121mol of Al2O3.
Convert this mole value to molar mass using mole = mass/molar mass
Molar mass of Al2O3 = 27(2) + 16(3)
= 54 + 48
= 102g/mol
mass = molar mass × mole
mass = 102 × 0.121
mass of Al2O3 = 12.34grams.