Answer:
Option a: positron emission.
Explanation:
In the transformation we have:
⁶⁷Ga → ⁶⁷Zn
The reaction is:

For Ga to become Zn, the atom nucleus has to lose a proton, so in the given options, the reaction that involves the transformation of a proton is the option a, positron emission.
In a positron emission, a proton becomes into a neutron and a positron:

Therefore, the correct answer is option a: positron emission.
I hope it helps you!
The ksp value for calcium hydroxide at this temperature is 5.20 × 10⁻⁶.
<h3>What is ksp?</h3>
Ksp is an equilibrium constant of a solid substance dissolved in a liquid solution.
Given that, the volume of water is 0.178 l, 0.264 g of Ca(OH)² dissolves in enough water
The solution equilibrium is
Ca(OH)² = Ca + 2OH
The molar solubility is
0.186 / 74.00 / 0.230 = 0.0109 M
The ksp value will be
Ksp = (s) (2S)²
Putting the values in the formula
(0.0109) x (2 x 0.0109)² = 5.20 × 10⁻⁶.
Thus, the ksp value for calcium hydroxide is 5.20 × 10⁻⁶.
To learn more about ksp value, refer to the link:
brainly.com/question/27132799
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there is a google calculator for this, but i don't know the exact formula.
Here is the chemical equation for gun powder, in it’s simple form:
<span>2 KNO3 + S + 3 C → K2S + N2 + 3 CO2.</span>
This is the same simplified formula, only balanced:
<span>10 KNO3 + 3 S + 8 C → 2 K2CO3 + 3 K2SO4 + 6 CO2 + 5 N2.</span>
The answer for the following problem is mentioned below.
- <u><em>Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule </em></u>
Explanation:
Given:
no of moles of the oxygen gas = 0.692
Also given:
2 HgO → 2 Hg + 
where,
HgO represents mercuric oxide
Hg represents mercury
represents oxygen
To calculate:
Molar mass of HgO:
Molar mass of HgO = 216 grams
molar mass of mercury (Hg) = 200 grams
molar mass of oxygen (O) =16 grams
HgO = 200 +16 = 216 grams
We know;
2×216 grams of HgO → 1 mole of oxygen molecule
? → 0.692 moles of oxygen molecule
= 
= 298.944 grams of HgO
<u><em>Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule </em></u>
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