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Ilia_Sergeevich [38]
3 years ago
5

Answer the following questions related to H2O.

Chemistry
1 answer:
sukhopar [10]3 years ago
8 0

Answer:

1. 8.8kJ/mol

2. The process is not favorable.

3. The reason is in the answer.

4. Process 1.

Explanation:

1. ΔG° = ΔG° products - ΔG° reactants

ΔG° = -228.4kJ/mol - (-237.2kJ/mol) = 8.8kJ/mol

2. The process is not favorable because ΔG > 0

3. As the reaction is an equilibrium, a little amount of water will change from liquid to gas. This is the reason because of water has a measurable equilibrium vapor pressure.

4. Entropy is greater in process 1 because the structure of H2O(s) is more organized than H2O(l) (S of H2O(s) is lower than H2O(l)).

ΔS of H2O(s)⇄H2O(g) is greater than H2O(l)⇄H2O(g)

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Solute concentration will afect the rate of a chemical reaction, because you must work with molarity

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I think that solute mass may be it can affect the rate of reaction, if you have more mass in a solute, you will also have more moles.

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Consider the reaction: N2(g) 2 O2(g)N2O4(g) Write the equilibrium constant for this reaction in terms of the equilibrium constan
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Answer : The equilibrium constant for this reaction is, K=\frac{(K_b)^2}{K_a}

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The intermediate reactions are:

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(2) \frac{1}{2}N_2(g)+O_2(g)\rightarrow NO_2(g);  K_b

We are reversing reaction 1 and multiplying reaction 2 by 2 and then adding both reaction, we get:

(1) 2NO_2(g)\rightarrow N_2O_4(g);  \frac{1}{K_a}

(2) N_2(g)+2O_2(g)\rightarrow 2NO_2(g);  (K_b)^2

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