Step-by-step explanation:
Hence, option A is the correct answer.
Answer:
A) g(t) = - 16*t² + 80*t
B) domain is ( 0 ≤ t ≤ 5 )
Step-by-step explanation:
A) for the model rocket
h = 0 and v = 80 feet/sec
Then the equation g(t) = -16*t² + v*t + h
became
g(t) = - 16*t² + 80*t + 0 g(t) = - 16*t² + 80*t
B) The equation g(t) = - 16*t² + 80*t is defined for all real numbers then the domain interval for t is ( -∞ , ∞ ). Now in our case, a model rocket was launched is not possible to get negative values for g(t) then the biggest value for t = 5 from
-16*t² + 80*t ≥ 0
-16*t ≥ -80 16*t ≤ 80
t ≤ 5
And the domain is ( 0 ≤ t ≤ 5 )
Answer:
199
Step-by-step explanation:
49 + 64 + 81 - 36 +25+16
194 - 36 +25 + 16
-36 + 25 + 16
= -11 + 16 = 5
194 + 5 = 199
Answer:
$2.25 per lb
Step-by-step explanation:
x = 4.50/2
x = $2.25 per lb
Answer:
21
Step-by-step explanation:
(fog)(3)= f( g(3) )
g(3)=6
plug back into expression
f(6)=21
thus,
(fog)(3)=21
