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yaroslaw [1]
4 years ago
8

Suppose you increase your walking speed from 4 m/s to 13 m/s in a period of 1 s. What is your acceleration? m/s2

Chemistry
1 answer:
777dan777 [17]4 years ago
4 0
Well the formula for a is a= { vf- vi} ÷ t
where vf is final velocity vi is initial velocity and t is time
thus substituting in the equation you get
a= {13-4} ÷ 1
= 9 m/s2 in the direction of Motion(acceleration is a vector)
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some infrared radiation reaches earth and sum does not with part does reach earth longer wave length or short wave length
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The answer is long wave length because long wave lengths contians less energy, and would not harm living things such as plants and animals. the more engey a wave length has, the less harmful it is.

short wave length: lots of energy, extremely hot. (examples: gamma rays, and UV (ultraviolet) rays.

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hopefully this helps.

4 0
3 years ago
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forsale [732]

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How many sig figs are in 340.0 mL
lyudmila [28]

Answer:

4

Explanation:

there is a decimal place present. so you would take away any zeros before the number.

5 0
3 years ago
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An acetate buffer solution is prepared by combining 50. mL of 0.20 M acetic acid,
natima [27]

Answer:

The answer is "Option B".

Explanation:

\to CH_3COOH + NaOH \longleftrightarrow  CH_3COONa + H_2O\\\\\to CH_3COONa + NaOH\longleftrightarrow CH3COONa\\\\\therefore \ mol\  NaOH = (5 \ E-3\  L)\times(0.10 \ \frac{mol}{L}) = 5 \ E-4\ mol\\\\

\to mol\ CH_3COOH = (0.05 \ L)\times(0.20 \frac{mol}{L}) = 0.01 \ mol\\\\\to C \ CH_3COOH = \frac{(0.01 \ mol - 5 \ E-4\ mol) }{(0.105 \ L)}\\\\\to C \ CH_3COOH = 0.0905 \ M\\\\\therefore \ mol \ CH_3COONa = (0.05\  L )\times (0.20 \ \frac{mol}{L}) = 0.01 \ mol\\\\

\to C \ CH_3COONa =  \frac{(0.01\  mol + 5 \ E-4\  mol)}{(0.105\ L )}\\\\\to C \ CH_3COONa = 0.1 \ M\\\\\therefore Ka = ([H_3O^{+}]\times \frac{(0.1 + [H_3O^+]))}{(0.0905 - [H_3O^+])} = 1.75\ E-5\\\\\to 0.1[H_3O^+] + [H_3O^+]^2 = (1.75 E-5)\times (0.0905 - [H_3O^+])\\\\

\to [H_3O^+]^2 \ 0.1[H_3O^+] = 1.584\  E-6 - 1.75\  E-5[H_3O^+]\\\\\to [H_3O^+]^2 + 0.1000175[H_3O^+] - 1.584 \ E-6 = 0\\\\\to  [H_3O^+] = 1.5835\  E-5 \ M\\\\\therefore pH = - \log [H_3O^+]\\\\\to  pH = - \log (1.5835 \ E-5)\\\\ \to pH = 4.8004 > 4.7

5 0
3 years ago
What is the hydrogen concentration of a solution with a pH of 2.1?
Black_prince [1.1K]

Answer:

8×10^(-3) mol/L

Explanation:

The formula for finding the hydrogen ion concentration is...

[H⁺] = 10^-ph

[H⁺] = 10^(-2.1)

[H⁺] = 0.00794...mol/L = 8×10^(-3) mol/L

The answer is to 1 significant digit because the pH has one decimal place.

5 0
3 years ago
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