Answer:
Explanation:
There are four quantum numbers:
Principal quantum number (n)
Azimuthal quantum number (l)
Magnetic quantum number (ml)
Spin quantum number (ms)
All these four quantum numbers gives complete information about an electron like its spin, shells, subshells and orbitals.
For example:
If l=3 than possible sets of quantum numbers are:
Azimuthal quantum number (l)
The azimuthal quantum number describe the shape of orbitals. Its value for s, p, d, f... are 0, 1, 2, 3. For l=3
(n-1)
4-1 = 3
it means principle quantum is 4 and electron is present in f subshell.
Magnetic quantum number (ml)
It describe the orientation of orbitals. Its values are -l to +l. For l=3 the ml will be -3 -2 -1 0 +1 +2 +3.
Spin quantum number (ms)
The spin quantum number tells the spin of electron either its clock wise (+1/2) or anti clock wise (-1/2).
If the electron is added in full empty orbital its spin will be +1/2 because it occupy full empty. If electron is already present and another electron is added then its spin will be -1/2.
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Answer:
Precent yield
Explanation:
This is takes into account how much of a substance should have been created (theoretical yield) and compares it to what was actually created (the actual yield).
Answer:
ΔH = -793,6 kJ
Explanation:
It is possible to obtain ΔH of this reaction using Hess's law that says you can sum the half-reactions ΔH to obtain the ΔH of the global reaction:
If half-reactions are:
1) H₂(g) + ¹/₂O₂(g) ⟶ H₂O(g) ΔH₁ = −241.8 kJ
2) X(s) + 2Cl₂(g) ⟶ XCl₄(s) ΔH₂ = +356.9 kJ
3) ¹/₂H₂(g) + ¹/₂Cl₂(g) ⟶ HCl(g) ΔH₃ = −92.3 kJ
4) X(s) + O₂(g) ⟶ XO₂(s) ΔH₄ = −639.1 kJ
5) H₂O(g) ⟶ H₂O(l) ΔH₅ = −44.0 kJ
The sum of (4) + 4×(3) - (2) - 2×(1) - 2×(5) is:
(4) X(s) + O₂(g) ⟶ XO₂(s) ΔH = −639.1 kJ
+4×(3) 2H₂(g) + 2Cl₂(g) ⟶ 4HCl(g) ΔH = −369,2 kJ
-(2) XCl₄(s) ⟶ X(s) + 2Cl₂(g) ΔH = -356,9 kJ
-2×(1) 2H₂O(g) ⟶ 2H₂(g) + O₂(g) ΔH = +483,6 kJ
-2×(5) 2H₂O(l) ⟶ 2H₂O(g) ΔH = +88.0 kJ
= <em>XCl₄(s) + 2H₂O(l) ⟶ XO₂(s) + 4HCl(g)</em>
Where ΔH is:
ΔH = -639,1 kJ -369,2 kJ -356,9 kJ +483,6 kJ +88,0 kJ
<em>ΔH = -793,6 kJ</em>
I hope it helps!