Answer:
The pH of the buffer is 7.0 and this pH is not useful to pH 7.0
Explanation:
The pH of a buffer is obtained by using H-H equation:
pH = pKa + log [A⁻] / [HA]
<em>Where pH is the pH of the buffer</em>
<em>The pKa of acetic acid is 4.74.</em>
<em>[A⁻] could be taken as moles of sodium acetate (14.59g * (1mol / 82g) = 0.1779 moles</em>
<em>[HA] are the moles of acetic acid (0.060g * (1mol / 60g) = 0.001moles</em>
<em />
Replacing:
pH = 4.74 + log [0.1779mol] / [0.001mol]
<em>pH = 6.99 ≈ 7.0</em>
<em />
The pH of the buffer is 7.0
But the buffer is not useful to pH = 7.0 because a buffer works between pKa±1 (For acetic acid: 3.74 - 5.74). As pH 7.0 is out of this interval,
this pH is not useful to pH 7.0
<em />
Answer:
deposition is the change from gas to solid
Answer:
363.64g of oxygen would be required.
Explanation:
1) Write and balance the combustion equation for propane.
Propane + Oxygen --> carbon dioxide + water
C3H8 + O2 --> CO2 + H2O
Upon balancing, we have;
C3H8 + 5O2 --> 3CO2 + 4H2O
2) How many grams of oxygen are required to burn 200 grams of propane.
From the reaction;
Propane = (3 * 12) + (8 * 1) = 44
Oxygen = (5 * 16) = 80
80 grams of oxygen is required to combust 44g of propane.
80 = 44
x = 200
x = ( 80 * 200 ) / 44
x = 363.64g
<u>Answer:</u> The final volume of the gas is 825.12 mL
<u>Explanation:</u>
To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,

where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:

Putting values in above equation, we get:

Hence, the final volume of the gas is 825.12 mL