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tankabanditka [31]
3 years ago
5

65 POINTS AND BRAINLIEST PLEASE HELP ASAP

Chemistry
1 answer:
Naily [24]3 years ago
3 0

Answer:

Rosalind Elsie Franklin (25 July 1920 – 16 April 1958)was a British biophysicist and X-ray crystallographer who made critical contributions to the understanding of the fine molecular structures of DNA, RNA, viruses, coal and graphite. The DNA work achieved the most fame because DNA (deoxyribonucleic acid) plays essential roles in cell metabolism and genetics, and the discovery of its structure helped scientists understand how genetic information is passed from parents to children.

rosalindfranklin

Franklin is best known for her work on the X-ray diffraction images of DNA which led to discovery of DNA double helix. Her data, according to Francis Crick, was "the data we actually used" to formulate Crick and Watson's 1953 hypothesis regarding the structure of DNA.Franklin's X-ray diffraction image confirming the helical structure of DNA were shown to Watson without her approval or knowledge. Though this image and her accurate interpretation of the data provided valuable insight into the DNA structure, Franklin's scientific contributions to the discovery of the double helix are often overlooked. Unpublished drafts of her papers (written just as she was arranging to leave King's College London) show that she had independently determined the overall B-form of the DNA helix and the location of the phosphate groups on the outside of the structure. However, her work was published third, in the series of three DNA Nature articles, led by the paper of Watson and Crick which only hinted at her contribution to their hypothesis.

After finishing her portion of the DNA work, Franklin led pioneering work on the tobacco mosaic and polio viruses. She died in 1958 at the age of 37 from complications arising from ovarian cancer.

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HELP!!!!!! 40 POINTS!!!!!!
elena55 [62]

Answer:

its B its B its B its B

Explanation:

3 0
3 years ago
Read 2 more answers
You wish to make a buffer with pH 7.0. You combine 0.060 grams of acetic acid and 14.59 grams of sodium acetate and add water to
aleksandr82 [10.1K]

Answer:

The pH of the buffer is 7.0 and this pH is not useful to pH 7.0

Explanation:

The pH of a buffer is obtained by using H-H equation:

pH = pKa + log [A⁻] / [HA]

<em>Where pH is the pH of the buffer</em>

<em>The pKa of acetic acid is 4.74.</em>

<em>[A⁻] could be taken as moles of sodium acetate (14.59g * (1mol / 82g) = 0.1779 moles</em>

<em>[HA] are the moles of acetic acid (0.060g * (1mol / 60g) = 0.001moles</em>

<em />

Replacing:

pH = 4.74 + log [0.1779mol] / [0.001mol]

<em>pH = 6.99 ≈ 7.0</em>

<em />

The pH of the buffer is 7.0

But the buffer is not useful to pH = 7.0 because a buffer works between pKa±1 (For acetic acid: 3.74 - 5.74). As pH 7.0 is out of this interval,

this pH is not useful to pH 7.0

<em />

7 0
3 years ago
Which term is defined as the phase change from gas to solid?.
const2013 [10]

Answer:

deposition is the change from gas to solid

5 0
2 years ago
Write and balance the combustion equation for propane. (Propane is combusted in the presence of oxygen to produce carbon dioxide
disa [49]

Answer:

363.64g of oxygen would be required.

Explanation:

1) Write and balance the combustion equation for propane.

Propane + Oxygen --> carbon dioxide + water

C3H8 + O2 --> CO2 + H2O

Upon balancing, we have;

C3H8 + 5O2 --> 3CO2 + 4H2O

2) How many grams of oxygen are required to burn 200 grams of propane.

From the reaction;

Propane = (3 * 12) + (8 * 1) = 44

Oxygen = (5 * 16) = 80

80 grams of oxygen is required to combust 44g of propane.

80 = 44

x = 200

x = ( 80 * 200 ) / 44

x = 363.64g

6 0
4 years ago
Read 2 more answers
The volume of a gas is 650. mL at 1.14°C. What will the volume be a 75.0°C?
tia_tia [17]

<u>Answer:</u> The final volume of the gas is 825.12 mL

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=650mL\\T_1=1.14^oC=(1.14+273)K=274.14K\\V_2=?mL\\T_2=75^oC=(75+273)K=348K

Putting values in above equation, we get:

\frac{650mL}{274.14K}=\frac{V_2}{348K}\\\\V_2=\frac{650\times 348}{274.14}=825.12mL

Hence, the final volume of the gas is 825.12 mL

3 0
3 years ago
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