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SVEN [57.7K]
3 years ago
12

I need help :(( please please easetriangle area ?​

Mathematics
1 answer:
kvasek [131]3 years ago
4 0

Answer:

\frac{25\sqrt{3}}{2}

Step-by-step explanation:

The area of a triangle is given by A=\frac{1}{2}bh where b is the base of the triangle and h is the height of the triangle. In a right triangle, the two legs will represent the base and height, both interchangeable.

In a 30-60-90 triangle, the sides are in the proportion x:x\sqrt{3}:2x, where 2x is the hypotenuse of the triangle and x is the side opposite to the 30 degree angle. Since the hypotenuse of this triangle is given as 10, the leg opposite to the 30 degree angle is equal to 10\div 2=5 and the leg adjacent to the 30 degree angle is equal to 5\sqrt{3}.

Thus, the area of this triangle is equal to:

A=\frac{1}{2}\cdot 5\cdot 5\sqrt{3}=\boxed{\frac{25\sqrt{3}}{2}}

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I NEED HELP ASAP<br>Evaluate the expression for r = –3. <br>15 + 6r =
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Since we are given the value of r, we can plug that value into the expression and solve.

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Me ajuda ai por favor tenho que entregar amanhã
elena-14-01-66 [18.8K]

a) (2a - b)² = (4a² - 4ab + b²)

b) (10m - n²)² = (100m² - 20mn² + n⁴)

c) (4x - 4²) = (16x² - 8x + 4⁴)

d){( \frac{1}{3} x - y) }^{2}  =  ({ \frac{1}{9}x }^{2}  -  \frac{2}{3} xy +  {y}^{2} )

e)

(0.25 - a) ^{2}  = (0.25^{2}  - (2)(0.25)a +  {a}^{2} ) \\  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \: \:  = ( \frac{1}{16}  -  \frac{1}{2} a +  {a}^{2} )

f)

{( \frac{2x}{3}  -  \frac{1}{2} )}^{2}  = ( \frac{4 {x}^{2} }{9}  -  \frac{2x}{3}   +  \frac{1}{4} )

6 0
3 years ago
Given a right triangle with legs a, b and hypotenuse c, solve for b if a= 72 and c= 75
kotykmax [81]

Answer:

The answer is a. 21.

Step-by-step explanation:

We solve this question by using Pythagoras theorem to relate the sides of a right angled triangle.

Here,

Hypotenuse of the given triangle(c)=75

Two sides of right angled triangle are:

a=72

b=?

Then,

for a given right angled triangle abc,

Using Pythagoras theorem,

c=\sqrt{a^{2} +b^{2} }

Squaring on both sides,

c^{2} =a^{2}+b^{2}

or,75^{2}=72^{2}+b^{2}

or, b^{2}=75^{2}-72^{2}

or,b^{2}=5625- 5184

or,b^{2} =441

∴b=21

So, the value of b is obtained to 21 by the use of Pythagoras theorem.

7 0
4 years ago
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