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jeka94
2 years ago
14

An object increases its velocity from 22 m/s to 36 m/s in 5 s. What is the acceleration of the

Physics
1 answer:
gregori [183]2 years ago
6 0

Explanation:

Using Kinematics,

we have a = (v - u) / t.

Therefore a = (36m/s - 22m/s) / 5s = 2.8m/s².

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A bus travels 280 km south along a straight path with an average velocity of 88 km/h to the south. The bus stops for 24 min, the
IgorC [24]

Answer:

76.78 km/h To calculate the average velocity for the total trip, you need to first determine the total distance traveled and the total time taken. First, let's calculate the total distance traveled. The trip consists of 2 legs. The 1st leg is 280 km and the 2nd leg is 210 km. So the total distance is 280 km + 210 km = 490 km. Now you need to calculate the total time taken. For this problem, there are 3 intervals that need to be accounted for. The travel time for the 1st leg, the duration of the rest stop in the middle, and the travel time for the 2nd leg. The travel time for both legs is calculated by dividing the distance traveled by the average speed. So for the first leg we have 280 km / (88 km / h) = 3.181818 h The 2nd leg is 210 km / (75 km/h) = 2.8 h The rest stop in hours is 24 min / (60 min/h) = 0.4 h The total time is 3.181818 h + 2.8 h + 0.4 h = 6.381818 h The average velocity is the distance divided by the time, giving: 490 km / (6.381818 h) = 76.78 km/h

Explanation:

Hope this helps!!

3 0
3 years ago
Read 2 more answers
The electric flux through a spherical surface is 1.4 ✕ 105 N · m2/C. What is the net charge (in C) enclosed by the surface?
Anit [1.1K]

Answer:

The  value is   Q_{net} =  1.239 *10^{-6} \  C

Explanation:

From the question we are told that

   The electric flux is \Phi =  1.4*10^{5} \  N\cdot m^2/C

     

Generally the net charge is mathematically represented as

    Q_{net} =  \Phi *  \epsilon_o

Here \epsilon_o is the permetivity of free space with value  

       \epsilon_o =  8.85*10^{-12}  \  \  m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2

So

   Q_{net} =  1.4*10^5 *  8.85*10^{-12}

=>   Q_{net} =  1.239 *10^{-6} \  C

8 0
3 years ago
A train moves moves from rest to a speed of 25 m/s in 30.0 sec . what is its acceleration
spayn [35]
A = Delta v/Delta t
Delta v = 25 - 0 = 25
Delta t = 30
25/30 = 5/6 = 1.66 repeating
7 0
2 years ago
Read 2 more answers
Why are “input” and “output” good words to use when discussing systems?
charle [14.2K]

Answer:

To determine how efficient that system is.

3 0
3 years ago
Read 2 more answers
Calculate the electrical energy use of the microwave in 120 V circuit has 7.5 A current flow, if it used for 0.05 hours
Elden [556K]

Answer:

162 KJ

Explanation:

The electrical energy can be calculated using the formula

E = V×I×t

Where, V= voltage = 120 V

I is current in ampere = 7.5 A and t is time in seconds

1 hour = 3600 sec

Therefore, 0.05 hour = 3600×0.05 = 180 sec

Substitute the values in above equation find electrical power

E = 120×7.5×180

= 162000 J

= 162 KJ

Therefore, the electrical energy use of the microwave = 162 KJ

3 0
2 years ago
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