All categories

2 years ago

In a cup game if the teams have the same score at the end of the match, 30 minutes of ------- are played.

Physics

1 answer:

Alina [70]2 years ago

5 0

Answer:

second lag

Explanation:

If in a cup game, a specified time limit is assigned to both teams to score high. If both teams are unable to score or if score of both the teams is equal then there is another second lag played where each team tries to score high. Even if in second lag both teams fail to score higher than other the last third lag is played or else game is declared draw.

You might be interested in

Suppose that two objects attract each other with a gravitational force of 50N. If the mass

vagabundo [1.1K]

Answer:

112.5 N

Explanation:

50 = GMm/r^2

Let F be the new force of attraction

F/50 = ( G(3M)(3m)/(2r)^2 ) / (GMm/r^2)

[Elimiating G,M,m,r]

F = 112.5 N

7 0

2 years ago

Where is the epicenter of the hypothetical earthquake as shown in the illustration below?

Genrish500 [490]

Answer:

Point D

Explanation:

The epicenter of a hypothetical earthquake is located at the point where the earthquake begins.

(See the attached image).

Hope it helps!

5 0

2 years ago

A worker lifts a 20.0-kg bucket of concrete from the ground up to the top of a 25.0-m tall building. The bucket is initially at

yuradex [85]

Answer:

Minimum work = 5060 J

Explanation:

Given:

Mass of the bucket (m) = 20.0 kg

Initial speed of the bucket (u) = 0 m/s

Final speed of the bucket (v) = 4.0 m/s

Displacement of the bucket (h) = 25.0 m

Let 'W' be the work done by the worker in lifting the bucket.

So, we know from work-energy theorem that, work done by a force is equal to the change in the mechanical energy of the system.

Change in mechanical energy is equal to the sum of change in potential energy and kinetic energy. Therefore,

$\Delta E=\Delta U+\Delta K\\\\\Delta E= mgh+\frac{1}{2}m(v^2-u^2)$

Therefore, the work done by the worker in lifting the bucket is given as:

$W=\Delta E\\\\W=mgh+\frac{1}{2}m(v^2-u^2)$

Now, plug in the values given and solve for 'W'. This gives,

$W=(20\ kg)(9.8\ m/s^2)(25\ m)+\frac{1}{2}(20\ kg)(4^2-0^2)\ m^2/s^2\\\\W=4900\ J +160\ J\\\\W=5060\ J$

Therefore, the minimum work that the worker did in lifting the bucket is 5060 J.

7 0

2 years ago

Jaden has a mass of 45 kilograms on Earth. Jupiter has more gravity than the Earth. On Jupiter, Jaden's mass will be O more than

Dovator [93]

Answer:

m = 45 kg

Explanation:

Given that,

Mass of Jadan, m = 45 kg on Earth

Jupiter has more gravity than the Earth.

Mass of an object is the amount of matter contained inside an object. We need to tell about the mass of Jaden on Jupiter. The mass of the object remains same everywhere.It does not change in any of the location.

Hence, Jaden's mass will be 45 kg on Jupiter.

7 0

2 years ago

This refers to the bending of a wave as it crosses a boundary between two media at an angle

Evgesh-ka [11]

The bending of a wave as it crosses a boundary between 2 mediums at an angle is called refraction.

3 0

3 years ago