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3 years ago

If an object triples its velocity, how does this effect its KE?

1 answer:

3 0

If an object triples its velocity then the kinetic energy become 9 times the initial kinetic energy. i hope this helped!

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A 100 N force causes an object to accelerate at 2 m/s2. What is the mass of the<br> object?

satela [25.4K]

Answer:

50 kg

Explanation:

Given,

Force ( F ) = 100 N

Acceleration ( a ) = 2 m/s^2

To find : Mass ( m ) = ?

Formula : -

F = ma

m = F / a

= 100 / 2

m = 50 kg

Therefore, the mass of the object is 50 kg.

5 0

3 years ago

The next two questions refer to this situation: A rectangular loop with sides of length a= 1.00 cm and b= 2.70 cm is placed near

alisha [4.7K]

Answer:

a) $1.007 * 10^{-7}$ V.m , into the page

b) $-5.39 * 10^{-8}$ V, counterclockwise

Explanation:

a) $d\Phi = B.dA\\\\B_r = \frac{\mu_0I}{2\pi r}\\\\dA = b.dr\\\\\Phi = \int\limits^b_a {B.dA} = \int\limits^{a+d}_d {\frac{\mu_0I}{2\pi r}.b.dr} =\frac{\mu_0I}{2\pi }.b.ln(\frac{a+d}{d} )\\$

At t = 2.90, I = 3.62 + 1.49 * (2.90)^2 = 16.15 A

$\Phi = \frac{4\pi * 10^{-7}*16.15*0.027}{2\pi} ln(1.46/0.46) = 1.007 * 10^{-7}$ V.m

Direction is into the page.

b) $emf = -d\Phi/dt = -\frac{\mu_0}{2\pi }.b.ln(\frac{a+d}{d}).(2.98t)= \\=-\frac{4\pi * 10^{-7}*0.027}{2\pi} ln(1.46/0.46)*2.98*2.90= -5.39 * 10^{-8} V$

Direction is counterclockwise.

8 0

3 years ago

You watch distant Sally Homemaker driving nails into a front porch at a regular rate of 1 stroke per second. You hear the sound

san4es73 [151]

Answer:

$d = 343 m$

Explanation:

As we know that the speed of sound in air is given as

$v = 343 m/s$

now the rate of strike is 1 stroke per second

so distance is given as

$d = v t$

now we will have

$t = 1 s$

$d = 343 \times 1$

so the distance is given as

$d = 343 m$

5 0

3 years ago

The rock is tied to a string and swung in a circular path by a

victus00 [196]

Answer:

6.3

Explanation:

6 0

3 years ago

RACTIC PTUDIES

Amanda [17]

Answer:

The illumination on the book before the lamp is moved is 9 times the illumination after the lamp is moved.

Explanation:

The distance of the book before the lamp is moved, $d_{b} = 30 cm$

The distance of the book after the lamp is moved, $d_{a} = 90 cm$

Illumination can be given by the formula, $E = \frac{P}{4 \pi d^{2} }$

Illumination before the lamp is moved, $E_{b} = \frac{P}{4 \pi d_{b} ^{2} }$

Illumination after the lamp is moved, $E_{a} = \frac{P}{4 \pi d_{a} ^{2} }$

$\frac{E_{a}}{E_{b}} } = \frac{\frac{P}{4 \pi d_{a} ^{2} } }{\frac{P}{4 \pi d_{b} ^{2} } }$

$\frac{E_{a} }{E_{b} } = \frac{d_{b} ^{2} }{d_{a} ^{2}} \\\frac{E_{a} }{E_{b} } = \frac{30^{2} }{90 ^{2}}\\\frac{E_{a} }{E_{b} } =\frac{900 }{8100}\\\frac{E_{a} }{E_{b} } =\frac{1 }{9}$

$E_{b} = 9E_{a}$

The illumination on the book before the lamp is moved is 9 times the illumination after the lamp is moved.

6 0

3 years ago