How do we know gravity is a field force?

Amanda [17]

Answer:130

Explanation:just answered it

4 0

3 years ago

Jessica's weight is 540 newtons. According to the Third Law, if the Earth pulls on Jessica with a force of 540 N, then Jessica p

Alja [10]

This is because the earth is way heavier than Jessica hence has a greater force of gravity applied on Jessica that Jessica applies to earth. The distance between the Earth and Jessica is also very short hence the force of gravity on Jessica towards earth is greater. According to Newton's laws that states; if an unbalanced force acts on an object, it will change the object's state of motion (the object will accelerate). The earth cause Jesica to ‘accelerate’ towards the ‘core’ when she stumbles.

8 0

3 years ago

Read 2 more answers

Anissa slides down a playground slide sloped at 25o. The coefficient of kinetic friction between Anissa and the slide is 0.15. I

Keith_Richards [23]

Answer:5.62 m/s

Explanation:

Given

Inclination $\theta =25^{\circ}$

Coefficient of kinetic Friction $\mu _k=0.15$

mass of Anissa's $m=55 kg$

time interval $t=2 s$

acceleration of the system

$a=g\sin \theta -\mu _kg\cos \theta$

$a=9.8\sin (25)-0.15\cdot 9.8\cos (25)$

$a=4.14-1.33=2.81 m/s^2$

$v=u+at$

where v=Final Velocity

u=Initial Velocity

a=acceleration of system

t=time

$v=0+2.81\times 2$

$v=5.62 m/s$

4 0

3 years ago

A projectile is fired from a height of 80 M above sea level, horizontally with a speed of 360 M / S, calculate: The time it take

Maslowich

Answer:

(a) The projectile takes approximately 4.420 seconds to reach the water, (b) The horizontal scope of the projectile is 1591.2 meters, (c) The remaining height to descend after 2 seconds of being launched is 63.624 meters.

Explanation:

The projectile experiments a parabolic motion, where horizontal speed remains constant and accelerates vertically due to the gravity effect. Let consider that drag can be neglected, so that kinematic equation are described below:

$x = x_{o}+v_{o,x} \cdot t$

$y = y_{o} + v_{o,y}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}$

Where:

$x_{o}$ , $y_{o}$ - Initial horizontal and vertical position of the projectile, measured in meters.

$v_{o,x}$ , $v_{o,y}$ - Initial horizontal and vertical speed of the projectile, measured in meters per second.

$t$ - Time, measured in seconds.

$g$ - Gravitational acceleration, measured in meters per square second.

$x$ , $y$ - Current horizontal and vertical position of the projectile, measured in meters.

Given that $x_{o} = 0\,m$ , $y_{o} = 80\,m$ , $v_{o,x} = 360\,\frac{m}{s}$ , $v_{o,y} = 0\,\frac{m}{s}$ and $g = -9.807\,\frac{m}{s^{2}}$ , the kinematic equations are, respectively:

$x = 360\cdot t$

$y = 80-4.094\cdot t^{2}$

(a) If $y = 0\,m$ , the time taken for the projectile to reach the water is:

$80 - 4.094\cdot t^{2} = 0$

$t = \sqrt{\frac{80}{4.094} }\,s$

$t \approx 4.420\,s$

The projectile takes approximately 4.420 seconds to reach the water.

(b) The horizontal scope is the horizontal distance done by the projectile before reaching the water. If $t \approx 4.420\,s$ , the horizontal scope of the projectile is:

$x = 360\cdot (4.420)$

$x = 1591.2\,m$

The horizontal scope of the projectile is 1591.2 meters.

(c) If $t = 2\,s$ , the height that remains to descend is:

$y = 80-4.094\cdot (2)^{2}$

$y = 63.624\,m$

The remaining height to descend after 2 seconds of being launched is 63.624 meters.

6 0

3 years ago

light that is polarized along the vertical direction is incident on a sheet of polarizing material. only 87% of the intensity of

nekit [7.7K]

Polarized light waves are those that have only one plane of vibration. Polarization is the process by which non-polarized light is converted into polarised light. There are numerous ways to polarise light.

A characteristic of transverse waves called polarisation identifies the geometric angle of the oscillations. A transverse wave's oscillation direction is perpendicular to the wave's motion direction.

given

Only 72.0% of the light's intensity makes it through the sheet and hits another sheet of polarising material. The second sheet lets no light flow through it.

Given that no light passes through the second sheet because both sheets are crossed, the angle the transmission axis of the second sheet makes with the vertical is

θ₂ = θ₁ + 90°

= 31.94° + 90°

= 1 21.94°

for the first sheet and

Icos²θ₁ = I

I/I₀ = 0.72

θ₁ = cos⁻¹√(0.72)

= 31.94°

for the second sheet, respectively. This is because the malus law states that I = Iocos²θ₁ for the first sheet.

To know more about light that is polarized, click on the link below:

brainly.com/question/3092611

#SPJ4

8 0

2 years ago