Heike Onnes noticed that pure, solid _____ could be cooled to 4.2 K and have no resistance.
1 answer:
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Answer:
The critical radius of the plastic insulation is 0.72 inches.
Explanation:
Given that,
Diameter = 0.091 in
Thickness = 0.02 in
Initial temperature = 90°F
Final temperature = 50°F
Heat transfer coefficient = 2.5 Btu/h.ft²°F
Material conductivity = 0.075 Btu/h.ft °F
We need to calculate the critical radius of the plastic insulation
Using formula of critical radius
Where, k = Material conductivity
h = Heat transfer coefficient
Put the value into the formula
Hence, The critical radius of the plastic insulation is 0.72 inches.