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4 years ago

Describe the octet rule.

Chemistry

1 answer:

raketka [301]4 years ago

4 0

Answer:

The octet rule is a chemical rule of thumb that reflects the observation that main group elements tend to bond in such a way that each atom has eight electrons in its valence shell, giving it the same electronic configuration as a noble gas.

Explanation:

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Polonium-208 undergoes alpha decay. In addition to the alpha

Yanka [14]

Answer:

Explanation:

7 0

3 years ago

Read 2 more answers

Phosgene, COCl2, gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide w

jek_recluse [69]

The question is incomplete, here is the complete question:

Phosgene, $COCl_2$ , gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide with chlorine:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

The value of $K_c$ for this reaction is 5.79 at 570 K. What are the equilibrium partial pressures of the three gases if a reaction vessel initially contains a mixture of the reactants in which $p_{CO}=p_{Cl_2}=0.265atm$ and $p_{COCl_2}=0.000atm$ ?

Answer: The equilibrium partial pressure of CO, $Cl_2\text{ and }COCl_2$ is 0.257 atm, 0.257 atm and 0.008 atm respectively.

Explanation:

The relation of $K_c\text{ and }K_p$ is given by:

$K_p=K_c(RT)^{\Delta n_g}$

$K_p$ = Equilibrium constant in terms of partial pressure

$K_c$ = Equilibrium constant in terms of concentration = 5.79

$\Delta n_g$ = Difference between gaseous moles on product side and reactant side = $n_{g,p}-n_{g,r}=1-2=-1$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

T = Temperature = 570 K

Putting values in above equation, we get:

$K_p=5.79\times (0.0821\times 570)^{-1}\\\\K_p=0.124$

We are given:

Initial partial pressure of CO = 0.265 atm

Initial partial pressure of chlorine gas = 0.265 atm

Initial partial pressure of phosgene = 0.00 atm

The given chemical equation follows:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial: 0.265 0.265

At eqllm: 0.265-x 0.265-x x

The expression of $K_p$ for above equation follows:

$K_p=\frac{p_{COCl_2}}{p_{CO}\times p_{Cl_2}}$

Putting values in above equation, we get:

$0.124=\frac{x}{(0.265-x)\times (0.265-x)}\\\\x=0.0082,8.59$

Neglecting the value of x = 8.59 because equilibrium partial pressure cannot be greater than initial pressure

So, the equilibrium partial pressure of CO = $(0.265-x)=(0.265-0.008)=0.257atm$

The equilibrium partial pressure of $Cl_2=(0.265-x)=(0.265-0.008)=0.257atm$

The equilibrium partial pressure of $COCl_2=x=0.008atm$

Hence, the equilibrium partial pressure of CO, $Cl_2\text{ and }COCl_2$ is 0.257 atm, 0.257 atm and 0.008 atm respectively.

6 0

3 years ago

Please help me i will mark brainliest

gulaghasi [49]

Answer:

7) Example: Gravitational force

Gravitational force, also known as gravity, is a type of non- contact force.

10) Unbalanced forces can cause an object to accelerate, make a stationary object move, or cause a moving object to stop.

12) Gravitational force, Frictional force, Magnetic force

13) Friction is beneficial when we are walking as it prevents us from slipping.

For the table, find the net force first and that would help us to find the direction and the type of force (balanced/ unbalanced).

As written in Q11, add all the forces together to determine the net force acting on an object. More specifically, add the forces that act in one direction together. Then subtract the forces acting in the other direction.

Let's look at the teddy bear (Q14 -16):

Take note that we have to look at the direction of the arrow not which side the arrow is on (left/ right of the bear).

Total force acting towards the left

= 16 +7

= 23N

Total force acting on the right= 22N

Net force

= 23 -22

= 1N towards the left

Thus, 14) Unbalanced (since the net force is not 0N)

15) 1N

15) 1N16) left

Vase question:

Total downward force

= 11 +33

= 44N

Total upward force

= 25 +19

= 44N

Net force= 0N

17) Balanced

17) Balanced18) 0N

17) Balanced18) 0N19) No direction

Bicycle question:

Total force acting towards the right

= 65 +115

= 180N

Total force to the left= 170N

Net force

= 180 -170

= 10N to the right

20) Unbalanced

20) Unbalanced21) 10N

20) Unbalanced21) 10N22) To the right

4 0

3 years ago

Is a hydrogel a smart polymer/stimuli-responsive polmer?

Vadim26 [7]

Polymer scientists have been trying to mimic this behavior by creating so called smart polymers. ... One of the most important classes of stimuli-responsive polymers used for controlled drug delivery is crosslinked polymer networks, e.g., hydrogels and microgels.
Hopefully this helps if not I’ll try rewriting it

8 0

3 years ago

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Give the systematic (IUPAC) names for these molecules. This molecule has the condensed formula C H 3 C H 2 C O O (C 6 H 5). C 6

scoundrel [369]

Answer:

The IUPAC name of the given compound is - Methyl - 4 - methylpentanoate

Explanation:

IUPAC name of the compound helps to determine the correct structure of the compound which can be used universally in order to avoid any confusion or misinterpretation.

$CH_3CH_2COO(C_6H_5)$

The IUPAC name of the given compound is - phenyl propanoate.

$CH_3OCOCH_2CH_2CH(CH_3)_2$

The IUPAC name of the given compound is - Methyl - 4 - methylpentanoate.

6 0

3 years ago