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yulyashka [42]
2 years ago
6

Guys help me, please

Chemistry
2 answers:
Ber [7]2 years ago
8 0

Answer:

radiation , conduction, convection, conduction

Pepsi [2]2 years ago
5 0

Answer:

radiation, conduction, convection, conduction

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4 0
1 year ago
how many grams of barium sulfate are produced if 10.0 grams of barium chloride are reacted is excess sulfuric acid​
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Answer: 11.2 grams

Explanation:

The balanced chemical equation for reaction is:

BaCl_2+H_2SO_4\rightarrow BaSO_4+2HCl

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of BaCl_2

\text{Number of moles}=\frac{10.0g}{208.23g/mol}=0.0480moles

According to stoichiometry :

As sulfuric acid​ is in excess , the limiting reagent is barium chloride as it limits the formation of product.

1 mole of BaCl_2 produces=  1 mole of BaSO_4

Thus 0.0480 moles of BaCl_2 require=\frac{1}{1}\times 0.0480=0.0480moles  of BaSO_4

Mass of BaSO_4=moles\times {\text {Molar mas}}=0.0480mol\times 233.38g/mol=11.2g

Thus 11.2 g of barium sulfate are produced if 10.0 grams of barium chloride are reacted is excess sulfuric acid​

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