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3 years ago

Organisms that reproduce sexually have offspring with greater variety. Which statement best explains this characteristic?

2 answers:

8 0

Organisms that reproduce sexually have offspring with greater variety because: B. The offspring get DNA from two parents, and it combines randomly.

Reproduction refers to a biological process through which living organisms (parents) mate to produce offspring.

Basically, there are two (2) main types of reproduction and these include;

Asexual reproduction.

Sexual reproduction.

During sexual reproduction, parent organisms produce offspring with greater variety because the genetic material of their parents are randomly combined to produce genetically-diverse offspring.

Artist 52 [7]3 years ago

8 0

Organisms that reproduce sexually have offspring with greater variety as a

result of offspring get DNA from two parents, and it combines randomly.

The DNA gotten from the daughter cells during meiosis involves the

production of unique cells from the parent cells

This is usually done by the daughter cells obtaining DNA from both parent

and combining randomly. It doesn't mutate regularly as mutation represents

defects which occurs in cells.

Read more on brainly.com/question/25411481

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Why do clumps of particles have slower reaction rates than particles that are separated?

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3 years ago

What is the percent yield of NH3 if the reaction of 26.3 g of H2 produces 79.0 g of NH3?

Anvisha [2.4K]

Answer:

$\boxed{\text{53.3 \%}}$

Explanation:

MM: 2.016 17.03

N₂ + 3H₂ ⟶ 2NH3

m/g: 26.3

1. Theoretical yield

(a) Moles of H₂

$\text{Moles of H${_2}$} = \text{26.3 g H${_2}$} \times \dfrac{\text{1 mol H${_2}$}}{\text{2.016 g H${_2}$}} = \text{13.05 mol H${_2}$}$

(b) Moles of NH₃

$\text{Moles of NH${_3}$} = \text{13.05 mol H${_2}$} \times \dfrac{\text{2 mol NH${_3}$}}{\text{3 mol H${_2}$}} = \text{8.697 mol NH${_3}$}$

(c) Theoretical yield of NH₃

$\text{Mass of NH${_3}$} = \text{8.967 mol NH${_3}$} \times \dfrac{\text{17.03 g NH${_3}$}}{\text{1 mol NH${_3}$}} = \text{148.1 g NH${_3}$}$

(d) Percent yield

$\text{Percent yield} = \dfrac{\text{ actual yield}}{\text{ theoretical yield}} \times 100 \% = \dfrac{\text{79.0 g}}{\text{148.1 g}} \times 100 \% = \textbf{53.3 \%}\\\\\text{The percent yield is }\boxed{\textbf{53.3 \%}}$

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3 years ago

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Please help thank you!

insens350 [35]

South east should be the answer

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3 years ago

Given that nitrogen forms three bonds with hydrogen to make <img src="https://tex.z-dn.net/?f=NH_%7B3%7D" id="TexFormula1" title

lbvjy [14]

Answer:

Three hydrogen atoms to form PH₃.

Explanation:

Hello!

In this case, since the elements belonging to the nitrogen family (N, P, As, Sb and Bi) show five valence electrons, because there are five electrons at their outer shell, it is clear that if phosphorous bonds with hydrogen, it is going to require the same amount of oxygen atoms (3) because elements having five valence electrons need 3 bonds in order to attain the octet (5+3=8).

Therefore the compound would be:

$PH_3$

Which is phosphine.

Best regards!

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3 years ago