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2 years ago

Organisms that reproduce sexually have offspring with greater variety. Which statement best explains this characteristic?

2 answers:

8 0

Organisms that reproduce sexually have offspring with greater variety because: B. The offspring get DNA from two parents, and it combines randomly.

Reproduction refers to a biological process through which living organisms (parents) mate to produce offspring.

Basically, there are two (2) main types of reproduction and these include;

Asexual reproduction.

Sexual reproduction.

During sexual reproduction, parent organisms produce offspring with greater variety because the genetic material of their parents are randomly combined to produce genetically-diverse offspring.

Artist 52 [7]2 years ago

8 0

Organisms that reproduce sexually have offspring with greater variety as a

result of offspring get DNA from two parents, and it combines randomly.

The DNA gotten from the daughter cells during meiosis involves the

production of unique cells from the parent cells

This is usually done by the daughter cells obtaining DNA from both parent

and combining randomly. It doesn't mutate regularly as mutation represents

defects which occurs in cells.

Read more on brainly.com/question/25411481

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Valence electrons Fill in the blanks

IgorC [24]

Answer:

Valence electrons or outer electrons are most important as they participate in bonding. The octet rule states that atoms gain, lose, or share valence electrons to have filled energy levels.. this gives atoms a stable configuration like that of the nearest noble gas.

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3 years ago

Im hvaing a hard time getting the right answer

Tanya [424]

Answer:

$V=23.9mL$

Explanation:

Hello!

In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:

$n=2.49g*\frac{1mol}{125.55 g}=0.0198mol$

Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:

$M=\frac{n}{V}\\\\V=\frac{n}{M}$

By plugging in the moles and molarity, we obtain:

$V=\frac{0.0198mol}{0.830mol/L}=0.0239L$

Which in mL is:

$V=0.0239L*\frac{1000mL}{1L}\\\\V=23.9mL$

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3 years ago

How many bromine atoms are present in 39.0 g of ch2br2?

Mandarinka [93]

Answer is: there is 2,69·10²³ atoms of bromine.
m(CH₂Br₂) = 39,0 g.
n(CH₂Br₂) = m(CH₂Br₂) ÷ M(CH₂Br₂).
n(CH₂Br₂) = 39 g ÷ 173,83 g/mol.
n(CH₂Br₂) = 0,224 mol.
In one molecule of CH₂Br₂, there is two bromine atoms, so:
n(CH₂Br₂) : n(Br) = 1 : 2.
n(Br) = 0,448 mol.
N(Br) = n(Br) · Na.
N(Br) = 0,448 mol · 6,022·10²³ 1/mol.
n(Br) = 2,69·10²³.

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3 years ago

3) Calculate the percent by mass of 3.55 g NaCl dissolved in 88 g water.

kotykmax [81]

Answer:

The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%

Explanation:

When a solute dissolves in a solvent, the mass of the resulting solution is a sum of the mass of the solute and the solvent.

A percentage is a way of expressing a quantity as a fraction of 100. In this case, the percentage by mass of a solution is the number of grams of solute per 100 grams of solution and can be represented mathematically as:

$Percent by mass=\frac{mass of solute}{mass of solution} *100$

In this way it allows to precisely establish the concentration of solutions and express them in terms of percentages.

In this case:

mass of solute: 3.55 g
mass of solution: 3.55 g + 88 g= 91.55 g

Replacing:

$Percentbymass=\frac{3.55}{91.55}*100$

Percent by mass= 3.88%

The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%

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3 years ago

How many particles are present in 8.0 moles of silver?

Zielflug [23.3K]

Answer:the answer is b

Explanation:I took the test and got it right

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