Answer:
Reduced, alkane
Explanation:
Wolf-Kishner reaction is a type of reduction reaction in which aldehydes and ketones are reduced to their corresponding alkane in the presence of a base.
This reaction occurs at high temperature.
Alkane formed has a same number of carbon as aldehyde and ketone.
If acetaldehyde undergoes a Wolf-Kishner reaction in the presence of base and heat, then ethane is formed. Nitrogen is formed as a byproduct.
Here, acetaldehyde is reduced to form ethane.
So, acetaldehyde undergoes a Wolf-Kishner reaction, which is the addition of hydrazine with subsequent addition of a base and heat. In this reaction, the aldehyde is reduced, resulting in alkane product.
Answer:
Explanation:
Hello,
In this case, since hydrochloric acid and barium hydroxide are in a 2:1 molar ratio, for the neutralization, the following moles equality must be obeyed:
In such a way, in terms of molarities and volumes, we can compute the required volume of hydrochloric acid as shown below:
Besr regards.
Answer:
The mass of 3.491 × 10¹⁹ molecules of Cl₂ of Cl₂ is 4.11 × 10⁻³ grams
Explanation:
The number of particles in one mole of a substance id=s given by the Avogadro's number which is approximately 6.023 × 10²³ particles
Therefore, we have;
One mole of Cl₂ gas, which is a compound, contains 6.023 × 10²³ individual molecules of Cl₂
3.491 × 10¹⁹ molecules of Cl₂ is equivalent to (3.491 × 10¹⁹)/(6.023 × 10²³) = 5.796 × 10⁻⁵ moles of Cl₂
The mass of one mole of Cl₂ = 70.906 g/mol
The mass of 5.796 × 10⁻⁵ moles of Cl₂ = 70.906 × 5.796 × 10^(-5) = 4.11 × 10⁻³ grams
Therefore;
The mass of 3.491 × 10¹⁹ molecules of Cl₂ of Cl₂ = 4.11 × 10⁻³ grams.
Answer:
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Answer:
2 KClO3 (s) = 2 KCl (s) + 3 O2 (g)
2.5 g x g
Explanation:
x g O2 = 2.5 g KClO3 x (1 mol KClO3) x (3 mol O2) x (32 g O2) = 0.98 g O2
(122.5 g KClO3) (2 mol KClO3) (1 mol O2)
2 KClO3 (s) 2 KCl (s) + 3 O2 (g)
2.5 g x g
x g KCl = 2.5 g KClO3 x (1 mol KClO3) x (2 mol KClO3) x (74.5 g KCl) = 1.52 g KCl
(122.5 g KClO3) (2 mol KClO3) (1 mol KCl)
2 KClO3 (s) 2 KCl (s) + 3 O2 (g)
x mol 10 mol
x mol KClO3 = 10 mol O2 x (2 mol KClO3) = 6.7 mol KClO3
(3 mol O2)
