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charle [14.2K]
3 years ago
5

How many moles are in 4.01x10^24 particles?

Chemistry
1 answer:
skelet666 [1.2K]3 years ago
6 0

Answer:

6.64

Explanation:

so moles

\frac{number  \: of \: \: particles \: }{6.02 \times  {10}^{23} }

then do =4.01×10^24/6.02×10^23

you get the answer as 6.6445 u only need to write the answer to

3.S.F 6.64 moles

hope this make sense :)

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Acetaldehyde (CH3CHO) undergoes a Wolf-Kishner reaction, which is the addition of hydrazine (H2NNH2) with subsequent addition of
Anarel [89]

Answer:

Reduced, alkane

Explanation:

Wolf-Kishner reaction is a type of reduction reaction in which aldehydes and ketones are reduced to their corresponding alkane in the presence of a base.

This reaction occurs at high temperature.

Alkane formed has a same number of carbon as aldehyde and ketone.

If acetaldehyde undergoes a Wolf-Kishner reaction in the presence of base and heat, then ethane is formed. Nitrogen is formed as a byproduct.

Here, acetaldehyde is reduced to form ethane.

So, acetaldehyde undergoes a Wolf-Kishner reaction, which is the addition of hydrazine  with subsequent addition of a base and heat. In this reaction, the aldehyde is reduced, resulting in alkane product.

6 0
3 years ago
How many Liters of 0.50M HCl are needed to neutralize 0.050L of 0.101M Ba(OH)2?
Aleksandr-060686 [28]

Answer:

V_{HCl}=5.05x10^{-3}L

Explanation:

Hello,

In this case, since hydrochloric acid and barium hydroxide are in a 2:1 molar ratio, for the neutralization, the following moles equality must be obeyed:

2*n_{HCl}=n_{Ba(OH)_2}

In such a way, in terms of molarities and volumes, we can compute the required volume of hydrochloric acid as shown below:

2*M_{HCl}V_{HCl}=M_{Ba(OH)_2}V_{Ba(OH)_2}\\\\V_{HCl}=\frac{M_{Ba(OH)_2}V_{Ba(OH)_2}}{2M_{HCl}} =\frac{0.101M*0.050L}{2*0.50M} \\\\V_{HCl}=5.05x10^{-3}L

Besr regards.

8 0
3 years ago
Read 2 more answers
Calculate the weight of 3.491 into 10 to the power 19 molecules of cl2​
Rom4ik [11]

Answer:

The mass of 3.491 × 10¹⁹ molecules of Cl₂  of Cl₂ is 4.11 × 10⁻³ grams

Explanation:

The number of particles in one mole of a substance id=s given by the Avogadro's number which is approximately 6.023 × 10²³ particles

Therefore, we have;

One mole of Cl₂ gas, which is a compound, contains 6.023 × 10²³ individual molecules of Cl₂

3.491 × 10¹⁹ molecules of Cl₂ is equivalent to (3.491 × 10¹⁹)/(6.023 × 10²³) = 5.796 × 10⁻⁵ moles of Cl₂

The mass of one mole of Cl₂ = 70.906 g/mol

The mass of 5.796 × 10⁻⁵ moles of Cl₂ = 70.906 × 5.796 × 10^(-5) = 4.11 × 10⁻³ grams

Therefore;

The mass of 3.491 × 10¹⁹ molecules of Cl₂  of Cl₂ = 4.11 × 10⁻³ grams.

4 0
3 years ago
Food undergoes both physical and chemical changes during digestion. Which parts of the digestive process listed below is a physi
sergeinik [125]

Answer:

To answer your question use the code ICE on here to get your answer works every time for me hope this helps

3 0
3 years ago
3.80 moles of oxygen are used up in the reaction. How many moles of water are produced?5.How many grams of oxygen does it take t
r-ruslan [8.4K]

Answer:

2 KClO3 (s) = 2 KCl (s) + 3 O2 (g)

2.5 g x g

Explanation:

x g O2 = 2.5 g KClO3 x (1 mol KClO3) x (3 mol O2) x (32 g O2) = 0.98 g O2

(122.5 g KClO3) (2 mol KClO3) (1 mol O2)

2 KClO3 (s) 2 KCl (s) + 3 O2 (g)

2.5 g x g

x g KCl = 2.5 g KClO3 x (1 mol KClO3) x (2 mol KClO3) x (74.5 g KCl) = 1.52 g KCl

(122.5 g KClO3) (2 mol KClO3) (1 mol KCl)

2 KClO3 (s) 2 KCl (s) + 3 O2 (g)

x mol 10 mol

x mol KClO3 = 10 mol O2 x (2 mol KClO3) = 6.7 mol KClO3

(3 mol O2)

7 0
3 years ago
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