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shepuryov [24]
3 years ago
15

What is the chemical symbol for dynamite?

Chemistry
2 answers:
valkas [14]3 years ago
7 0
The chemical symbol is C3H5
gizmo_the_mogwai [7]3 years ago
6 0
Dynamite is not an element.

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germanium -66 has a half-life of 2.5 hours. you have 35 grams of radioactive material. after 16 days, how much radioactive mater
Maru [420]

Hey there!

A half-life means after a certain amount of time, half of that substance will be gone/changed after that time.

How many half-lives are in 16 days?

Multiply 16 by 24 (to get the total hours) and divide that by 2.5.

That is 153.6 half-lives.

35(0.5)^(153.6) represents the equation for this.

Simplify this and get 8.88 x 10^(-45).

There will be 2.02 x 10^(-45)g of germanium-66 sample remaining after 16 days.

Hope this helps!

6 0
3 years ago
Bromine (Br2) is produced by reacting HBr with O2, with water as a byproduct. The O2 is part of an air (21 mol % O2, 79 mol % N2
Karolina [17]

Answer:

The mole fractions:

x_{HBr}=\frac{100mol}{318.5}=0.314

x_{Br_2}=\frac{78mol}{318.5}=0.245

x_{H_2O}=\frac{78mol}{318.5}=0.245

x_{O_2}=\frac{62.5mol}{318.5}=0.196

Explanation:

The reaction described is:

2 HBr (g) + 1/2 O_2 (g) \longrightarrow Br_2 (g) + H_2O (g)

The limiting reactant is the HBr (oxygen is in excess).

a) The mass (in moles) balance for this sistem:

n_{Br_2}=\frac{ 1 mol Br_2}{1 mol HBr} *n_{HBr}*0.78

(the 0.78 is because of the fractional conversion)

n_{O_2}=\frac{ 0.5 mol O_2}{1 mol HBr} *n_{HBr}*1.25

(the 1.25 is because of the oxygen excess)

n_{H_2O}=\frac{ 1 mol H_2O}{1 mol Br_2} *n_{Br_2}

There is only one degree of freedom in this sistem, you can either deffine the moles of HBr you have or the moles of Br2 you want to produce. The other variables are all linked by the equations above.

b) Base of calculation 100 mol of HBr:

nn_{HBr}=100 mol HBr

n_{Br_2}=\frac{ 1 mol Br_2}{1 mol HBr} *100mol HBr*0.78

n_{Br_2}=78 mol Br2

n_{O_2}=\frac{ 0.5 mol O_2}{1 mol HBr} *100 mol HBr*1.25

n_{O_2}=62.5 mol O_2

n_{H_2O}=n_{Br_2}= 78 mol

n_{total}=(78+78+100+62.5)mol= 318.5mol

The mole fractions:

x_{HBr}=\frac{100mol}{318.5}=0.314

x_{Br_2}=\frac{78mol}{318.5}=0.245

x_{H_2O}=\frac{78mol}{318.5}=0.245

x_{O_2}=\frac{62.5mol}{318.5}=0.196

4 0
3 years ago
B) How does electron gain enthalpy change along a period and in a group?​
chubhunter [2.5K]

Answer:

Electron gain enthalpy becomes more and more negative from left to right in a period. As we move across a period from left to right the atomic size decreases and the nuclear charge increases

3 0
3 years ago
Read 2 more answers
What is the mole-to-mole ratio between N2 and H2?
spin [16.1K]
Remember, look at the coefficients in the balanced equation! Here are three mole ratios:
1 mole<span> N2 / </span>3 moles<span> H2.</span>
3 moles<span> H2 / 2 moles NH3.
</span>


5 0
3 years ago
An atom has 32 protons, 40 neutrons, and 32 electrons. What is the charge of the atom’s nucleus?
eimsori [14]
The charge is neutral.

To find the charge, subtract the number of electrons from the number of protons. Because they are the same, there is no charge.
8 0
3 years ago
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