An organism with no natural enemies is called

When an ionic solid is added into a solvent, you can see that the ionic solid dissociates into its respective cations and anions

SVEN [57.7K]

The order of the steps, from first to last, is as follows based on the information in the question:

1. Salt is broken down into cations and anions.

2. Anion hydration.

3. Cation hydration.

4. Cations and anions that have been dissolved start to settle as a solid salt.

5. The rate of dissolution and recrystallization are equal.

Without hydration of the ions, the cation and anion cannot get separated. The three processes of ion dissociation, cation hydration, and anion hydration must all take place at once.

<h3>Why water is an effective solvent?</h3>

Water is a great solvent that can dissolve a wide variety of compounds due to its polarity and capacity to create hydrogen bonds.

Learn more about solvation here:

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4 0

2 years ago

The oxidation of Cu₂O(s) to CuO(s) is an exothermic process:

Alex73 [517]

Answer:

w = 7376.6 J

Explanation:

To calculate the work done in the system, we need first to calculate the number of moles of all compounds.

The following expression, that comes from the 1° law of thermodynamic, will help you to get the work:

w = ΔnRT

Where:

Δn: difference in the number of moles between products and reactants

R: constant universal of gases (8.314 J / mol K)

T: Temperature in Kelvin.

As we are doing this reaction in STP, then the Pressure is 1 atm, and temperature is 0 °C or 273 K.

Now, we already have the moles of Cu₂O, let's see, according to the balanced reaction, how many moles we should have of O₂ and CuO.

If 1 mole of O₂ reacts with 2 moles of Cu₂O then 6.5 moles of Cu₂O will be:

moles O₂ = 6.5 moles Cu₂O * (1 mole O₂/2 moles Cu₂O) = 3.25 moles O₂

If 2 moles of Cu₂O produces 4 moles of CuO, then 6.5 moles will be:

moles CuO = 6.5 moles Cu₂O*(4 moles CuO/2 moles Cu₂O) = 13 moles CuO

Now that we have the moles, let's calculate the value of Δn.

Δn = moles product - moles reactants

Δn = 13 - (6.5 + 3.25) = 3.25 moles

Now, we can calculate the work done in the system:

w = 3.25 * (8.314 * 273)

Hope this helps

8 0

2 years ago

Mrs. Johnson's science class perform an experiment. They combine two substances that react with lots of fizzing and bubbling. Th

s2008m [1.1K]

Chris is correct because the reactants and products do not have to have the same mass, but they do have to weigh the same. Is the correct answer:) Hannah is right because the mass of the reactants was different than the mass of the products. is incorrect

3 0

3 years ago

Read 2 more answers

One mole of an ideal gas is contained in a cylinder with a movable piston. The temperature is constant at 77°C. Weights are remo

frozen [14]

Answer:

The total work is 4957.45J

Explanation:

For an ideal gas, at constant temperature the definition of work (W) is

$W = - P.dV = - n.R.T \int\limits^i_f {\frac{dV}{V} \\W = - n.R.T. Ln (\frac{V_{f}}{V_{I}})\\W = - n.R.T. Ln (\frac{P_{i}}{P_{f}})$

where P is the pressure, V the volume, n the moles number, T the temperature and R the gas constant.

To solve the problem is necessary to replace the two steps in the equation

Stape 1: n = 1 mol, R = 0.082atm.L/K.mol, T = 77ºC = 350K, Pi = 5.50atm and Pf = 2.43atm.

$W_{1} = - 1molx0.082\frac{atm.L}{K.mol}x350KxLn (\frac{5.50atm}{2.43atm}) = 23.44atm.Lx101.325\frac{J}{atm.L} =2375.44J$

Stape 2: n = 1 mol, R = 0.082atm.L/K.mol, T = 77ºC = 350K, Pi = 2.43atm and Pf = 1.00atm.

$W_{2} = - 1molx0.082\frac{atm.L}{K.mol}x350KxLn (\frac{2.43atm}{1.00atm}) = 25.48atm.Lx101.325\frac{J}{atm.L} =2582.01J$

The total work is the sum of the two steps

$W = W_{1} + W_{2} = 2375.44J + 2582.01J = 4957.45J$

4 0

3 years ago

Atmospheric pressure decreases as altitude increases. in other words, there is more air pushing down on you at sea level, and th

LuckyWell [14K]

Boiling point is the temperature at which vapour pressure equals atmospheric pressure.

As, we move at higher altitudes, atmospheric pressure decreases. Hence, temperature to reach the boiling point will decrease.

Further, boiling point is higher for longer chain compounds. Hence,<span> octane (C8H18) and octanol (C8H17OH) will have higher boiling point as compared to hexane (C6H14). Further, intermolecular forces of interaction are more stronger in octanol, due to presence of OH group, as compared to octane.

Hence, boiling points will be in following order:
Octanol > Octane > Hexane

Thus, hexane will boil first, followed by octane and lastly octanol.</span>

7 0

2 years ago