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harkovskaia [24]
3 years ago
8

An organism with no natural enemies is called

Chemistry
2 answers:
Archy [21]3 years ago
7 0

Answer:

it is pathogens i think its that

Explanation:

vampirchik [111]3 years ago
7 0
Not sure !!!!!!!!!!!!
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An aqueous solution containing 17.5 g of an unknown molecular (nonelectrolyte) compound in 100.0 g of water has a freezing point
Sonbull [250]

Answer:

molar mass = 180.833 g/mol

Explanation:

  • mass sln = mass solute + mass solvent

∴  solute: unknown molecular (nonelectrolyte)

∴ solvent: water

∴ mass solute = 17.5 g

∴ mass solvent =  100.0 g = 0.1 Kg

⇒ mass sln = 117.5 g

freezing point:

  • ΔTc = - Kc×m

∴ ΔTc = -1.8 °C

∴ Kc H2O = 1.86 °C.Kg/mol

∴ m: molality (mol solute/Kg solvent)

⇒ m = ( - 1.8 °C)/( - 1.86 °C.Kg/mol)

⇒ m = 0.9677 mol solute/Kg solvent

  • molar mass (Mw) [=] g/mol

∴ mol solute = ( m )×(Kg solvent)

⇒ mol solute = ( 0.9677 mol/Kg) × ( 0.100 Kg H2O )

⇒ mol solute = 0.09677 mol

⇒ Mw solute = ( 17.5 g ) / ( 0.09677 mol )

⇒ Mw solute = 180.833 g/mol

6 0
3 years ago
Which is one way that Dalton's atomic theory has been shown to be incorrect?
KATRIN_1 [288]
The answer is D. His belief is was that atoms could not be split. That is what was disproved really fast ;)
6 0
3 years ago
PLZ HELP I WILL GIVE BRAINLISTS TO RIGHT ANSWER
galina1969 [7]
..........The answer is B
6 0
3 years ago
In a solution, what term is given to the liquid?
Jet001 [13]

Answer: solvent

solvent is  A solvent is usually a liquid

7 0
3 years ago
Read 2 more answers
If a 0.4681 g Mg strip reacts with 0.650 M HCl in a 139.3 mL flask at 25oC, what is the minimum volume (mL) of HCl needed to com
Marizza181 [45]
The reaction between the magnesium, Mg, and the hydrochloric acid, HCl is given in the equation below,

    Mg + 2HCl --> H2 + MgCl2

The number of moles of HCl that is needed for the reaction is calculated below.
    n = (0.4681 g Mg)(1 mol Mg/24.305 g Mg)(2 mol HCl/1 mol Mg)
    n = 0.0385 mols HCl

From the given concentration, we calculate for the required volume. 
    V = 0.0385 mols HCl/(0.650 mols/L)
     V = 0.05926 L or 59.26 mL

<em>Answer: 59.26 mL of HCl</em>
7 0
3 years ago
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