All categories

3 years ago

Help please Derive an equationTa=1.44T1/2

Physics

1 answer:

Anna11 [10]3 years ago

3 0

Explanation:

To derive an equation you must indicate the variable you want to solve for.

Here we have tension of an object A and Tension 1.

Two variables or unknown are given hence we cannot derive any other equations.

You might be interested in

What is the repulsive force between two pith balls that are 9.00 cm apart and have equal charges of -28.0 nC?

Alexus [3.1K]

Answer:

Force, $F=8.71\times 10^{-4}\ N$

Explanation:

Given that,

Charges on pith balls, $q_1=q_2=-28\ nC=-28\times 10^{-9}\ C$

Distance between balls, d = 9 cm = 0.09 m

Let F is the repulsive force between two pith balls. We know that the repulsive force between two charges is given by :

$F=k\dfrac{q_1^2}{d^2}$

$F=9\times 10^9\times \dfrac{(-28\times 10^{-9})^2}{(0.09)^2}$

F = 0.000871 N

$F=8.71\times 10^{-4}\ N$

So, the repulsive force between the pith balls is $8.71\times 10^{-4}\ N$ . Hence, this is the required solution.

7 0

4 years ago

Explain how the sun's position in the sky would change the direction of your shadow if you were to stand in the same place all d

rusak2 [61]

Shadows move in the opposite direction to the sun. Since the sun changes position throughout the day this alters the direction and position of your shadow

4 0

4 years ago

A Astronut Went To Space With Two Materials A Flag And Pen Weight 5000kg Calculate The Weight Of Two Materials?

djverab [1.8K]

You have to divide both objects to get the answer

6 0

3 years ago

Give reasons. A revolving stone tied in a string files away when the string breaks.

Anastaziya [24]

It is cause of the intertia of direction

when the string breaks the force acting on the stone ceases

without the force the stone flies away along the tangent of circular path

hope that helped :))

3 0

4 years ago

a carnot engine absorbs 200J of heat from a reservoir at the temperature of the normal boiling point of water and rejects heat t

emmainna [20.7K]

Answer:

The heat rejected is 146J.

The work done by the engine is 54J.

The thermal efficiency is 0.27

Explanation:

The efficiency of the carnot engine, which is working between a hot source at a temperature $T_{1}$ and a cold source at a temperature $T_{2}$ , is given by:

$Efficiency=1-\frac{T_{2}}{T_{1}}$

The normal boiling point of water is 373 K. ( $T_{1}$ )

The temperature of triple point of water is 273.15 K ( $T_{2}$ )

$Efficiency=1-\frac{273.15}{373}=0.27$

$Efficiency=\frac{Work\:done}{Heat\:absorbed}=\frac{Work\:done}{200}=0.27\\Work\:done=0.27\times200=54J\\Work\:done=Heat\:absorbed-Heat\:rejected\\Heat\:rejected=Heat\:absorbed-Work\:done=200-54=146J$

6 0

4 years ago

Help please Derive an equationTa=1.44T1/2​​

Help please Derive an equationTa=1.44T1/2