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PIT_PIT [208]
3 years ago
14

We are trying to reduce the current time of 15s by 30% but this leads to an increase of 18% in the CPI. For each processor, what

clock rate should we have to achieve this time reduction?
Physics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0

Answer:

Explanation:

For reduction

Execution time = (instructions * CPI)/(Clock rate)

Since CPI is increased by 18%

18/100 +1 = 1.18

Therefore

P1 CPI = CPI x 1.18

P2 CPI = CPIx 1.18

P3 CPI = CPI x 1.18

Since clockrate reduces by 30% we have it to be a 0.7

P1: (Instructions x P1CPI) / 0.7

P2: (Instructionsx P2CPI) / 0.7

P3: (Instructions x P2CPI) /0 .7

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Group 7A of the periodic table contains the?
olga2289 [7]

The correct answer is A. Most reactive non metals.

Firstly if some one knows how to read the periodic table he would have no confusion in deciding whether group 7 has metals or non metals. Group 7 contains non metals so basically we can easily cancel out two options of metals.

Secondly group 7 non metals are the most reactive non metals as they need only one electron in order to complete their valence shell and become stable.


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3 years ago
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A positive point charge q is placed at the center of an uncharged metal sphere insulated from the ground. The outside of the sph
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Explanation:

the missing figure in the Question has been put in the attachment.

Then from the figure we can observe that

the center of the sphere is positive, therefore, negative charge will be  induced at A.

As B is grounded there will not be any charge on B

Hence the answer is A is negative and B is charge less.

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3 years ago
A 1-kg rock is suspended from the tip of a horizontal meterstick at the 0-cm mark so that the meterstick barely balances like a
tigry1 [53]

Explanation:

Given that,

Mass if the rock, m = 1 kg

It is  suspended from the tip of a horizontal meter stick at the 0-cm mark so that the meter stick barely balances like a seesaw when its fulcrum is at the 12.5-cm mark.

We need to find the mass of the meter stick. The force acting by the stone is

F = 1 × 9.8 = 9.8 N

Let W be the weight of the meter stick. If the net torque is zero on the stick then the stick does not move and it remains in equilibrium condition. So, taking torque about the pivot.

9.8\times 12.5=W\times (50-12.5)\\\\W=\dfrac{9.8\times 12.5}{37.5}

W = 3.266 N

The mass of the meters stick is :

m=\dfrac{W}{g}\\\\m=\dfrac{3.266}{9.81}\\\\m=0.333\ kg

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5 0
3 years ago
What is the current when the resistance is 5 ohms and the voltage is 10 volts?
Travka [436]
Ohm's Law states V = IR
So,
I = V/R
The answer is B. 10/5=2 amps
5 0
3 years ago
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What is the length a rubberband was stretched if it has a spring constant of 5700N/m and is currently holding 8600J OF POTENTIAL
lozanna [386]

Answer:

\displaystyle \Delta x=1.74\ m

Explanation:

<u>Elastic Potential Energy </u>

Is the energy stored in an elastic material like a spring of constant k, in which case the energy is proportional to the square of the change of length Δx and the constant k.

\displaystyle PE = \frac{1}{2}k(\Delta x)^2

Given a rubber band of a spring constant of k=5700 N/m that is holding potential energy of PE=8600 J, it's required to find the change of length under these conditions.

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Substituting:

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\displaystyle \Delta x=\sqrt{3.0175}

\boxed{\displaystyle \Delta x=1.74\ m}

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3 years ago
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