Answer:
a) No
b) No
Explanation:
When a bat is hit in a game of baseball such that it flies out of the field that means it is going with some angle to the horizontal.
a)
Then is such a case the velocity of the ball is never parallel to the acceleration because there acts a net acceleration which is resultant of the acceleration due to the applied force and the acceleration due to gravity but a component of the velocity when the ball descends the height acts parallel to the gravity.
b)
At no point during the motion of the ball its velocity is perpendicular to its acceleration because it has an initial angle of projection form the horizontal.
Kg are weight, m are length lol soooooo
Explanation:
explain more the question
The velocity at the maximum height will always be 0. Therefore, you will count your final velocity as 0, and your initial velocity as 35 m/s. Next, we know that the acceleration will be 9.8 m/s^2. How? Because the ball is thrown directly upward, and the only force acting on it will be the force of gravity pushing it back down.
The formula we use is h = (Vf^2 - Vi^2) / (2*-9.8m/s^2)
Plugging everything in, we have h = (0-1225)/(19.6) = 62.5 meters is the maximum height.
Answer:
Explanation:
Assume the rod is horizontal
Sum vertical forces to zero
F - 8 - 4 - 2 - 3 = 0
F = 17 N
While this result answers precisely the question asked, it is not sufficient to guarantee equilibrium. We must also locate this force by summing moments to zero. Let's choose to sum about the left end.
8[9/2] + 4[1] + 2[6] + 3[4] - 17[x] = 0
x = 3.76470588...
the force must be supplied upward approximately 3.765 m from the left end
The rod does not actually have to be horizontal. Moment arms will all be proportionately reduced by tilting the bar from horizontal and the results will be identical. Assuming horizontal just reduces the calculation effort.