The engine is 10,000 N I think. Hopefully this helps!!
Answer:
3.69 m/s
Explanation:
Forces :
mgsin Θ - mumgcosΘ = ma
g x sinΘ - mu x g x cosΘ = a
9.8 x sin 21 - 0.53 x 9.8 x cos 21 = a
a = -1.337 m/s²
so you have final velocity = 0 m/s
initial velocity = ? m/s
Given d = 5.1 m
By kinematics
vf² = vo² + 2ad
0 = vo² + 2 x -1.337*5.1
vo = 3.69 m/s
Explanation:
It is given that,
Weight of the rock in air, W = 110 N
Since, W = mg


m = 11.22 kg
We need to find the apparent weight of the rock when it is submerged in water. Apparent weight is equal to the weight of liquid displaced i.e.

d is the density of water, 
V is the volume of rock, 

M = 3.37 kg
The apparent weight in water, W = m - M

W = 76.93 N
So, the apparent weight of the rock is 76.93 N. Hence, this is the required solution.
Based on the description, it will be most likely that he believes in Oscillating model (also known as Cyclic model) of the universe
Based on this model, the gravitational force will prevent further expansion by pulling back the matters and undergo a bounce
hope this helps
Answer:
0.541 nm
Explanation:
The condition for maxima is,

Here, m=0,1,2,.....
And d is the slit separation, m is the order of maxima,
is the wavelength.
Given that, the 17.3 eV electron posses a wavelength of

And the order of maxima is
.
And the angle at which first order maxima occur is,
.
Put these values in maxima condition while solving for d.

Therefore, the slit separation is 0.541 nm.