Answer:
HCO₂
Explanation:
From the information given:
The mass of the elements are:
Carbon C = 26.7 g; Hydrogen H = 2.24 g Oxygen O = 71.1 g
To determine the empirical formula;
First thing is to find the numbers of moles of each atom.
For Carbon:

For Hydrogen:

For Oxygen:

Now; we use the smallest no of moles to divide the respective moles from above.
For carbon:

For Hydrogen:

For Oxygen:

Thus, the empirical formula is HCO₂
Answer:
See explanation.
Explanation:
Since potassium tert-butoxide is a strong bulky base, we expect that an elimination reaction predominates.
This reaction is expected to occur by E2 mechanism. The cis isomer of 1-bromo-4-tert-butylcyclohexane is known to react faster by E2 mechanism because it fulfills the anticoplanar arrangement required for for E2 mechanism, where the leaving group and adjacent proton must be anti to each other and in the same plane. The trans isomer can not fulfill this requirement.
The component of the dri reflects the requirement of a nutrient for 50 percent of healthy americans and canadians in a specific life stage and gender is Estimated Average Requirement (EAR).
What is EAR?
A daily food intake number known as the Estimated Average Requirement (EAR) is one that is thought to satisfy the needs of 50% of healthy persons in a given life stage and gender group.
Based on a review of the scientific literature, the estimated average requirements (EAR) are predicted to meet the needs of 50% of the population in that age range.
It serves as the foundation for the creation of RDAs and is employed to assess the sufficiency of nutritional consumption for a given population.
To learn more about EAR click the given link
brainly.com/question/14449512
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The correct Anwser is enzymes
Answer:
12
Explanation:
You will need a chemical equation with masses and molar masses, so let’s gather all the information in one place.
: 258.21 18.02
KAl(SO₄)₂·xH₂O ⟶ KAl(SO₄)₂ + xH₂O
Mass/g: 4.74 2.16
Step 1. Calculate the mass of the KAl(SO₄)₂.
Mass = 4.74 g – 2.16 g = 2.58 g.
Step 2. Calculate the moles of each product.


Step 3. Calculate the molar ratio of the two products.

1 mol of KAl(SO₄)₂ combines with 12 mol H₂O, so x = 12.