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valina [46]
4 years ago
5

HELP PLEASE THE OTHER 'ANSWER' ISNT EVEN AN ANSWER!

Chemistry
1 answer:
hodyreva [135]4 years ago
4 0

Answer:

most likely that (2) the replicated experiment was performed incorrectly.

Why, u ask? u dare question me:

1- The initial experiment invalidness cannot be proven.

2- <em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>s</u></em><em><u>e</u></em><em><u>c</u></em><em><u>o</u></em><em><u>n</u></em><em><u>d</u></em><em><u> </u></em><em><u>a</u></em><em><u>n</u></em><em><u>s</u></em><em><u>w</u></em><em><u>e</u></em><em><u>r</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>c</u></em><em><u>o</u></em><em><u>r</u></em><em><u>r</u></em><em><u>e</u></em><em><u>c</u></em><em><u>t</u></em>

3- Different labaratories does not effect the outcome, as long as the parameter and environment of the replicated experiment is the same as when the initial experiment was conducted.

4- Already knowing the data and errors would increase the precision of the replicated experiment.

5- Change in variables should still be in the objective (or purpose) of the experiment, thus, major difference in the outcome should not happen.

happy learning!

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A basketball rolling across a flat floor has ____energy.
Elden [556K]

Answer:

kinetic energy

Explanation:

8 0
3 years ago
Lead (II) chloride (PbCl2) has a Ksp of 1.17 x 10-5. Calculate the molar solubility of PbCl2, in moles per liter. Enter your ans
bixtya [17]

Answer:

1.43 * 10^-2

Explanation:

Firstly, we need to get the ionization equation for lead I chloride. We can then get the Initial, change and equilibrium table of the lead and chloride ions that can help us calculate the molar solubility. This is shown as follows:

PbCl2(s) --> Pb2+(aq) + 2 Cl-(aq)

This shows that one mole of lead ii chloride will yield 1 mole of the lead ion and 2 moles of the chloride ion.

The ICE table is shown below:

Pb2+ 2Cl-

Initial 0.00 0.00

Change +s +2s

Equilibrium s 2s

Ksp = [Pb2+][Cl-]^2

Ksp = [s][2s]^2

Ksp = 4s^3

s^3 = Ksp/4

s = cube.root [Ksp/4]

s = cube.root[1.17 * 10^-5/4]

s = 1.43 * 10^-2

3 0
3 years ago
Chromium-48 decays. After 6 half-lives, how much of the original nuclei would remain if we started with 600 g?
maw [93]

Answer:

1

Explanation:

2

3 0
3 years ago
12.5 g of copper are reacted with an excess of chlorine gas, and 25.4 g of copper(II) chloride are
Alika [10]

Answer:

Percent yield = 94.5%

Theoretical yield =  26.89 g

Explanation:

Given data:

Mass of copper = 12.5 g

Mass of copper chloride produced = 25.4 g

Theoretical yield = ?

Percent yield = ?

Solution:

Cu + Cl₂  →  CuCl₂

Number of moles of Copper:

Number of moles = mass/ molar mass

Number of moles = 12.5 g/ 63.55 g/mol

Number of moles = 0.2 mol

Now we will compare the moles of copper with copper chloride.

          Cu          :           CuCl₂

           1             :              1

          0.2          :            0.2

Theoretical yield:

Mass of copper chloride:

Mass = Number of moles × molar mass

Mass = 0.2 mol × 134.45 g/mol

Mass = 26.89 g

Percent yield:

Percent yield = Actual yield / theoretical yield  × 100

Percent yield = 25.4 g/26.89 g × 100

Percent yield = 94.5%

8 0
4 years ago
Given the problem below, what would the first step be in solving it?
Hoochie [10]

Answer:

First step would be convert to moles

Final Answer: 37.8 g of NaCl

Explanation:

The reaction is:

2Na + Cl₂ → 2NaCI

We convert the mass of each reactant to moles:

18 g . 1mol /23g = 0.783 moles of Na

23g . 1mol / 70.9g = 0.324 moles of chlorine

We use the mole ratio to determine the limiting reactant:

Ratio is 2:1. 2 moles of Na react to 1 mol of chlorine

Then, 0.783 moles of Na, may react to (0.783 . 1)/2 = 0.391 moles.

Excellent!. We need 0.391 moles of Cl₂ and we only have 0.324 moles available. That's why the Cl₂ is our limiting reactant.

We use the mole ratio again, with the product side. (1:2)

1 mol of Cl₂ can produce 2 moles of NaCl

Then, our 0.324 moles of gas, may produce (0.324 . 2)/1 = 0.648 moles

Finally, we convert the moles to grams:

0.648 mol . 58.45g/mol =

4 0
3 years ago
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