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3 years ago

HELP PLEASE THE OTHER 'ANSWER' ISNT EVEN AN ANSWER!

Chemistry

1 answer:

hodyreva [135]3 years ago

4 0

Answer:

most likely that (2) the replicated experiment was performed incorrectly.

Why, u ask? u dare question me:

1- The initial experiment invalidness cannot be proven.

2- the second answer is correct

3- Different labaratories does not effect the outcome, as long as the parameter and environment of the replicated experiment is the same as when the initial experiment was conducted.

4- Already knowing the data and errors would increase the precision of the replicated experiment.

5- Change in variables should still be in the objective (or purpose) of the experiment, thus, major difference in the outcome should not happen.

happy learning!

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B. The equilibrium constant for the reaction 2H2(g) + S2(g) 2H2S(g) is Keq = . (3 points)

eimsori [14]

Answer:

i. Keq=4157.99.

ii. More hydrogen sulfide will be produced.

Explanation:

Hello,

i. In this case, for the concentrations at equilibrium on the given chemical reaction, the equilibrium constant results:

$Keq=\frac{[H_2S]^2}{[H_2]^2[S_2]} =\frac{(0.97M)^2}{(0.051M)^2(0.087)} =4157.99$

ii. Now, by means of the Le Chatelier's principle, the addition of a reactant shifts the reaction towards products, it means that more hydrogen sulfide will be produced in order to reach equilibrium.

Best regards.

4 0

3 years ago

For the reaction below, if the rate of appearance of Br2 is 0.180 M/s, what is the rate of disappearance of

brilliants [131]

Answer:

–0.360 M/s

Explanation:

7 0

3 years ago

If 100.0 grams of na3n decompose to form sodium and nitrogen, how many moles of sodium are formed? write and balance equation be

Yakvenalex [24]

The balanced equation is:
$2Na_3N-\ \textgreater \ 6Na + N_2$

Then proceed with the following equations.

$100g Na_3N*(\frac{1molNa_3N}{82.98gNa_3N})*(\frac {6mol Na}{2molNa_3N})*(\frac {22.99gNa}{1molNa})=83.12gNa$

The answer is $83.12gNa$ .

7 0

3 years ago

Read 2 more answers

Predict the effect of the following changes in the reaction CO (g) + 2 H2 (g) <-> CH3OH (g) + energy.

Sophie [7]

Explanation:

Equation of reaction:

CO + 2H₂ ⇒ CH₃OH + energy

a. An increase in pressure:

A change in pressure affects only equilibrium involving a gas or gases. Le Chatelier's principle can be used to predict the direction of displacement.

An increase in pressure on an equilibrium system will shift the position of equilibrium to the side having smaller volume and vice-versa

CO + 2H₂ ⇒ CH₃OH + energy

3 moles 1 moles

An increase in pressure will favor the forward reaction to be favored.

b. Addition of H₂:

An in concentration of a specie favors the direction that uses up that specie and lowers its concentration.

Addition of hydrogen gas increases the concentration of amount of substances reacting.

To annul the effect of the reactant, more the product is given. The equilibrium shifts in the forward direction.

learn more:

equilibrium brainly.com/question/5877801

#learnwithBrainly

8 0

3 years ago

Ammonia can be produced via the chemicalreaction

otez555 [7]

Answer:

3)The reaction is not at equilibrium and willproceed to the right.

Explanation:

The reaction quotient of an equilibrium reaction measures relative amounts of the products and the reactants present during the course of the reaction at particular point in the time.

It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.

Q < Kc , reaction will proceed in forward direction.

Q > Kc , reaction will proceed in backward direction.

Q = Kc , reaction at equilibrium.

Given that:

Q = $3.56\times 10^{-4}$

K = $6.02\times 10^{-2}$

Since, Q < K , reaction is not at equilibrium and will proceed to right, in forward direction.

3 0

3 years ago