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user100 [1]
3 years ago
13

Consider this equilibrium:

Chemistry
2 answers:
Ierofanga [76]3 years ago
7 0

Answer:

It decreases as the concentration of products decreases.

It increases as the concentration of products increases.

Explanation:

the equilibrium reaction is

N_{2}(g)+O_{2}(g)2NO(g)

As per equilibrium,

a) there will be no effect of pressure change on the equilibrium as the number of gaseous molecules are same on both the side of reaction.

b) there will be no effect of addition of inert gas on the equilibrium as the number of gaseous molecules are same on both the side of reaction.

c) the reverse reaction rate can be increased by

i) decreasing the concentration of reactants

ii) increasing the concentration of products

zheka24 [161]3 years ago
3 0
It is C). <span>It decreases as the concentration of products increases.</span>
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Calculate the mole fraction of each component in a solution with 6.87 g of sodium chloride (NaCl) dissolved in 65.2 g of water.
zheka24 [161]

Answer:

mole fraction of NaCl = 0.03145.

mole fraction of water = 0.9686.

Explanation:

  • Mole fraction is an expression of the concentration of a solution or mixture.
  • It is equal to the moles of one component divided by the total moles in the solution or mixture.
  • The summation of mole fraction of all mixture components = 1.

mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles).

<em>no. of moles of NaCl = mass/molar mass </em>= (6.87 g)/(58.44 g/mol) = 0.1176 mol.

<em>no. of moles of water = mass/molar mass</em> = (65.2 g)/(18.0 g/mol) = <em>3.622 mol.</em>

<em></em>

∴ mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles) = (0.1176 mol)/(0.1176 mol + 3.622 mol) = 0.03145.

<em>∵ mole fraction of NaCl + mole fraction of water = 1.0.</em>

∴ mole fraction of water = 1.0 - mole fraction of NaCl = 1.0 - 0.03145 = 0.9686.

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