Answer:
1.
work out the mean mode median and range
Explanation:
Answer:
—96.03°C
Explanation:
We'll begin by writing out the information provided by the question. This includes:
Number of mole (n) = 0.645 mole
Volume (V) = 2.00 L
Pressure (P) = 4.68 atm
Temperature (T) =?
Recall: that the gas constant = 0.082atm.L/Kmol
With the ideal gas equation PV = nRT, the temperature of the gas can be obtained as follow:
PV = nRT
4.68 x 2 = 0.645 x 0.082 x T
Divide both side 0.645 x 0.082
T = (4.68 x 2) /(0.645 x 0.082)
T = 176.97 K
Now, We can also express the temperature obtained in celsius as shown below:
Temperature (celsius) = temperature (Kelvin) - 273
Temperature (celsius) = 176.97 - 273
Temperature (celsius) = —96.03°C
The temperature of the Neon gas is
—96.03°C
Explanation:
Since methane gas is at 1 atm and 273 K, it is at standard temperature and pressure(STP).
One mole of every gas occupies 22.4 dm^3 at STP, and vice versa. So,
22.4 dm^3 at STP of CH4=1 mol=12+4(1)=16 g
0.462 L(0.462 dm^3) at STP of CH4
=(16 g×0.462 dm^3)/22.4 dm^3
=0.33 g
