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3 years ago

Glucose is a simple sugar made up of a carbon, hydrogen, and oxygen. What kind of molecule is glucose?

Chemistry

2 answers:

Alina [70]3 years ago

8 0

Glucose falls under aldoses group of monosaccharides which are one of the carbohydrates.

Explanation:

Generally, a molecule formed by combination of carbon, hydrogen and oxygen are termed as carbohydrates. The smallest of the saccharides are mono and disaccharides. The saccharides can contain an aldehyde or a ketone group in their structural formula.

The molecular formula of glucose is C6H12O6. It falls under monosaccharide as the molecular formula of monosaccharides are (CH2nO)n where the n will be 3,5 or 6. So the molecular formula of glucose exactly matches with the molecular formula of monosaccharide family.

Also, it is known that glucose contains an aldehyde so it can be termed as aldose for being a carbohydrate in monosaccharide family containing aldehyde group.

jasenka [17]3 years ago

4 0

Answer:

Glucose is nothing but a type of carbohydrate molecule which is also called as monosaccharides.

Explanation:

They are the smallest unit or simplest part of Carbohydrates which accumulates and join together to make bigger molecules of carbohydrates, Since these are made up of carbon, hydrogen, and oxygen.

These three elements mix together in given parts to make this smallest part of Carbohydrates or sugar. The Other bigger carbohydrates that are formed with these three elements are disaccharides or sucrose.

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Calculate the pH for each of the following cases in the titration of 50.0 mL of 0.210 M HClO(aq) with 0.210 M KOH(aq).

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35.0 mL of 0.210 M
KOH molarity = moles/volume
find moles of OH do the same thing for: 50.0 mL of 0.210 M HClO(aq) but for H+ they will cancel out: H+ + OH- -> H2O
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zubka84 [21]

Answer:

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3 years ago

H2CO3(aq) + H200 H30 (aq) + HCO3 (aq).

timofeeve [1]

Answer:

$K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}$

Explanation:

Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:

an equilibrium constant is, first of all, a fraction;
in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
each concentration should be raised to the power of the coefficient in the balanced chemical equation;
only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.

Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:

$K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}$

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