Answer:
(a) Elongation of rod = 0.19732 mm
(b) Change in diameter = 0.00651 mm
Explanation:
Circular area at end of steel rod = pi * diameter^2 / 4
Area = 3.801 * 10^(-4) meter squared
Stress = force / area
Stress = 75000 / (3.801 * 10^-4)
Stress = 197316495 Pa OR 0.197 GPa
Modulus of elasticity = stress / strain
200 = 0.19732 / Strain
Strain = 0.0009866 (longitudinal)
(a) Strain = change in length / initial length
0.0009866 = Elongation of rod / 200
Elongation of rod = 0.19732 mm
(b) Poisson ratio = lateral strain / longitudinal strain
0.3 = lateral strain / 0.0009866
Lateral strain = 0.000296
Lateral strain = Change in diameter / original diameter
0.000296 = Change in diameter / 22
Change in diameter = 0.00651 mm
Answer
given,
initial speed of the car (v₁)= 19.8 mi/h
final speed of the car (v₂)= 59.9 mi/h
a) initial momentum = m v₁
P₁ = 19.8 m
final final momentum = m v₂
P₂ = 59.9 m
ratio =
=
ratio of momentum=
b) initial kinetic energy= 1/2 m v₁²
K₁ = 196.02 m
final kinetic energy= 1/2 m v₂²
K₂ = 1794.005 m
ratio =
=
ratio of Kinetic energy=
Answer:
The acceleration of the box is 2.
Explanation:
According to Newton's second law of motion, the acceleration of any object will be directly proportional to the net unbalanced force acting on the object and inversely proportional to the mass of the object.
Net force = Mass × Acceleration
So
Since in this case, the box is experiencing a force from east of magnitude 27 N and resisting force of about 17 N from west. So the net force will be the difference of acting and reacting force.
Net force = 27-17 = 10 N.
Thus,
So 2 is the acceleration of the box. Thus the magnitude of acceleration of the box is 2.
