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fredd [130]
3 years ago
9

calculate the volume of a 3.0 mol of oxygen, b 50.0g of hydrogen cloride gas at STP(molar volume of gas is 22.4dm³,molar mass of

Hcl=36.5g)​
Chemistry
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

98L is the volume of the gas

Explanation:

To solve this question we need to find  the moles of O2 + moles HCl. With these moles and PV = nRT we can find the volume as follows:

<em>Moles O2: </em>3.0mol

<em>Moles HCl:</em>

50.0g * (1mol/36.5g) = 1.37 moles HCl

<em>Total moles:</em>

3.0mol O2 + 1.37 mol HCl = 4.37 moles

PV = nRT

V = nRT/P

<em>Where V is volume in L, n are moles = 4.37mol, R is gas constant = 0.082atmL/molK, T is absolute temperature = 273.15K at STP, P = 1atm at STP</em>

V = 4.37mol*0.082atmL/molK*273.15K / 1atm

V = 98L is the volume of the gas

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Explanation:

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n  =  moles of NH₄NO₃  =  8.00 g NH₄NO₃  ×  1 mol NH₄NO₃/80.0 g NH₄NO₃          

∴ n =   0.100 mol NH₄NO₃

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ΔHsoln  =  +2570.19 J  /0.100 mol  =  +25702 J/mol  =  +25.7 kJ/mol

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