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2 years ago

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What is the percent yield if 3.47 g of copper is produced when 1.87 g of aluminium is reacted with excess of copper (II) sulfato

? 2Al(s)+3CuSO4(ag)-Al2(SO4)3+3Cu(s)

1 answer:

Serhud [2]2 years ago

5 0

Answer:

copper is limiting

Explanation:

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Dr. Patel and her team have been using GPS to track two plates that are moving toward each

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C: One plate is going underneath the other plate and sinking into the soft rock below.

Explanation:

Where plates are moving towards each other they are said to converging, and are called convergent margins.

The lithosphere is broken into series of slabs called plates. The plates moves on the weak and relatively soft asthenosphere below.

Plates have different motion. At some places, they move apart and they are said to be divergent.

When plates moves towards each other, they are convergent. At a convergent margin, a plate collides with another thereby causing the denser plate usually the oceanic plate to subduct into the asthenosphere. In some other cases, the plates can collide and build upward.

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3 years ago

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Troyanec [42]

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This is for chemistry:/

Andreyy89

Answer:

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3 years ago

How many neutrons are in an atom of tin? Round your answer to the nearest whole number.

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There are 50 neutrons in and atom of tin.

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3 years ago

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If 10.0 grams of NaHCO3 is added to 10.0 g of HCl, determine the efficiency of baking soda as an antacid if 6.73 g of NaCl was p

Lapatulllka [165]

Answer:

percentage yield of NaCl = 96.64%

Explanation:

The reaction was between NaHCO3 and HCl .The chemical equation can be represented below:

NaHCO3 + HCl → NaCl + H2O + CO2 . The balance equation is

NaHCO3 + HCl → NaCl + H2O + CO2

The question ask us to calculate the percentage yield of NaCl.

The efficiency of NaHCO3 as an antacid , the limiting reactant is NaHCO3

as

1 mole of NaHCO3 produces 1 mole of NaCl

Therefore,

molar mass of NaHCO3 = 23 +1 + 12 + 48 = 84 g

molar mass of NaCl = 23 + 35.5 = 58.5 g

1 mole of NaHCO3 = 84 g

1 mole of NaCl = 58.5 g

since 84 g of NaHCO3 produces 58.5 g of NaCl

10 g of NaHCO3 will produce ? grams of NaCl

cross multiply

Theoretical yield of NaCl = (10 × 58.5)/84

Theoretical yield of NaCl = 585/84

Theoretical yield of NaCl = 6.9642857143 g

percentage yield of NaCl = actual yield/theoretical yield × 100

percentage yield of NaCl = 6.73/6.9642857143 × 100

percentage yield of NaCl = 673/6.9642857143

percentage yield of NaCl = 96.635897436%

percentage yield of NaCl = 96.64%

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3 years ago

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