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Leni [432]
3 years ago
5

A gas has a volume of 350 mL at 318.15 K. If the volume changes to 4.00 L, what is the new temperature?

Chemistry
1 answer:
enot [183]3 years ago
7 0
28°C.
Explanation:
The correct equation to use with these kinds of questions is the Combined Gas Law.
P
1
⋅
V
1
T
1
=
P
2
⋅
V
2
T
2
This equation, though, is a little unnecessary at times because of the possibility of extra constants.
In this case you have a pressure constant which enables us to shorten your longer equation down to Charles' Law because pressure remains the same and doesn't affect the calculation.
V
1
T
1
=
V
2
T
2
The next step is to isolate the variable that you want, which is, in this case,
T
2
.
T
2
=
V
1
T
1
V
2
Now it is time to replace your known variables with numbers
T
2
=
350
m
L
⋅
45
°
C
400
m
L
And calculate...
T
2
=
28.125
°
C
Significant digits...
T
2
=
28
°
C
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Answer:

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Lastly, Snape thinks we should try one more calculation. What is the retention factor if the distance traveled by the solvent fr
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Answer:

0.1 is the retention factor.

Explanation:

Distance covered by solvent ,d_s= 2.0 cm

Distance covered by solute or ion,d = 0.20 cm

Retention factor(R_f) is defined as ratio of distance traveled by solute to the distance traveled by solvent.

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3 years ago
Which can lead scientists to change a theory that has already been accepted? Check all that apply. changes to scientific laws ne
Romashka-Z-Leto [24]

Answer:

New experimental methods

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Explanation:

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What is the average atomic mass of chlorine if the mass of one isotope is 34.97 amu and has a p?er cent abundance of 75.77%. The
pishuonlain [190]

Answer : The average atomic mass of chlorine is, 32.37 amu

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

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Percentage abundance of isotope 1 = 75.77 %

Fractional abundance of isotope 1 = 0.7577

Mass of isotope 2 = 36.97 amu

Percentage abundance of isotope 2 = 24.23 %

Fractional abundance of isotope 2 = 0.2423

Now put all the given values in above formula, we get:

\text{Average atomic mass of element}=\sum[(34.97\times 0.7577)+(24.23\times 0.2423)]

\text{Average atomic mass of element}=32.37amu

Therefore, the average atomic mass of chlorine is, 32.37 amu

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