Explanations:
<u>Question</u> <u>1:</u> Lithium in 20.00+ g is C. or D., but 25.00+ g is D. which means this is the correct option.
I am unsure of <u>Question</u> <u>2</u>. I don't think it is mole though.
<u>Question</u> <u>3:</u> Boron in 25.00-30.00 g is B. or D., but 25.00 g would be C.
<u>Question</u> <u>4:</u> 2.393 x 1024 atoms of Oxygen is 63.58 mole O. I don't know for sure, but I think this is correct.
<u><em>I am NOT professional. There is a chance I am incorrect. Please reply to me if I've made a mistake.</em></u>
You would know that the variable is quantitative if it shows any number to express the quantity. For example, quantitative variables are 50°C, 5 atm, 2 moles, 100 L and so on. A variable is qualitative if it expresses a relative quantity but not expressing a number. Examples would be: few, too hot, several, or even describing the characteristics of a variable. Hence, when the variable is in grams, then that would be quantitative.
Answer:
Explanation:
2S + 3O₂ = 2SO₃
2moles 3 moles
2 moles of S react with 3 moles of O₂
5 moles of S will react with 3 x 5 / 2 moles of O₂
= 7.5 moles of O₂ .
O₂ remaining unreacted = 10 - 7.5 = 2.5 moles .
All the moles of S will exhausted in the reaction and 2.5 moles of oxygen will be left .
Answer:
Option c. Neutral
Explanation:
Only neutral solution gives a green colouration to a pH paper
Answer:
Time = 0.929s = 0.93s (2 s.f)
Explanation:
Rate constant, k = 34.1 M^-1s^-1
Initial Concentration, [A]o = 0.100M
Time = ?
Final Concentration [A] = 0.0240M
The parameters are represented in the following equation as;
1/[A] = kt + 1/[A]o
kt = 1/[A] - 1/[A]o
kt = 1/0.0240 - 1/0.1
kt = 31.67
t = 31.67 / 34.1
t = 0.929s = 0.93s (2 s.f)
