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adell [148]
3 years ago
5

What is the asteroid's name? a. Bubbles b. Carl c. Bennu d. Rex

Chemistry
2 answers:
castortr0y [4]3 years ago
8 0

Answer:

I would say Bennu

Explanation:

Hope this was correct! Let me know if i need to correct it please =w=

Virty [35]3 years ago
3 0

Answer:

d. rex

Explanation:

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Make the following conversion. 120 mL = _____ cm³ <br><br> 12.0<br> 1200<br> 120<br> 1.20
Lina20 [59]
The correct answer would be 120.
4 0
3 years ago
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Which chemicals are major contributors to ozone layer destruction? Select two answer choices.
gulaghasi [49]

Answer: <em>Chlorine and Bromine</em>

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3 years ago
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The atomic weight of Ga is 69.72 amu. There are only two naturally occurring isotopes of gallium:
irga5000 [103]

Answer:

71 Ga has a naturally abundance of 36%

Explanation:

Step 1: Given data

Gallium has 2 naturally occurring isotopes: this means the abundance of the 2 isotopes together is 100 %. The atomic weight of Ga is 69.72 amu. This is the average of all the isotopes.

Since the average mass of 69.72 is closer to the mass of 69 Ga, this means 69 Ga will be more present than 71 Ga

Percentage 69 Ga> Percentage 71 Ga

<u>Step 2:</u> Calculate the abundance %

⇒Percentage of 71 Ga = X %

⇒Percentage of 69 Ga = 100 % - X %

The mass balance equation will be:

100*69.72 = x * 71 + (100 - x)*69

6972 = 71x + 6900 -69x

72 = 2x

x = 36 %

71 Ga has a naturally abundance of 36%

69 Ga has a naturally abundance of 64%

3 0
4 years ago
Draw structure of oxygen, nitrogen &amp;methane.​
Elina [12.6K]

See the image below-⬇⬇-

Hope this helps :D

4 0
3 years ago
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If the half-life of a radioactive substances is 590 million years and you have 40 atoms of it, how many half-lives will have pas
Nady [450]

Answer:

3

Explanation:

Applying,

2^{n'} = R/R'............... Equation 1

Where n' = number of halflives that have passed, R = Original atom of the substance, R' = atom of the substance left after decay.

From the question,

Given: R = 40 atoms, R' = 5 atoms

Substitute these values into equation 1

2^{n'} = 40/5

2^{n'} = 8

2^{n'} = 2³

Equation the base,

n' = 3

3 0
3 years ago
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