Answer:
A) 1.68 L
Explanation:
- Charles’ Law states that: at constant pressure, the volume is directly proportional to the temperature of the gas.
- It can be expressed as: V₁T₂ = V₂T₁,
V₁ = 1.2 L, T₁ = 175.0 K, V₂ = ??? L, T₂ = 245.0 K.
∴ V₂ = V₁T₂/T₁ = (1.2 L)(245.0 K)/(175.0 K) = 1.68 L.
The reduction of a less active metal by a more active one is called metal displacement reactions. For example:
Fe + CuSO4 → FeSO4 + Cu
<h3>What is metal displacement reaction? </h3>
Displacement reactions is a reaction which includes a metal and the compound of a other metal. A more reactive metal will push or displace out a less reactive metal from its compound in this displacement reaction. The metal which is less reactive left uncombined after the reaction.
As we know that, electrons are the basis of the chemical reactions. If chemical compound or element A is more easily oxidized than B, then according to the terms of the activity series, the elements which are more easily oxidized can react with more chemicals, since they are able to act as a reducing agents for more chemicals.
Since, Metal ions are positively charged ions as they lose electrons. Some metals give up their electrons more readily than others and become more reactive.
Thus, we concluded that the reduction of a less active metal by a more active one is called metal displacement reactions. For example:
Fe + CuSO4 → FeSO4 + Cu
learn more about metal displacement reaction:
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The two are Celsius and Kelvin. the most used is Kelvin. the reason is that it is more precise measurement.
2 mol of Sodium hydroxide (NaOH) reacts to form 1 mol of sodium sulfate (Na_2SO_4)
- 1 mol of NaOH produces 1/2 mol sodium sulfate.
3.7moles of Na OH produces
- 1/2(3.7)=1.8mol sodium sulfate
Answer:
116.3 grCO2
Explanation:
1st - we balance the equation so that it finds the same amount of elements of the product side and of the reagent side
C6H6 +15/2 O2⟶ 6CO2 +3 H2O
2nd - we calculate the limiting reagent
39.2gr C6H6*(240grO2/78grC6H6)=120 grO2
we don't have that amount of oxygen so this is the excess reagent and oxygen the limiting reagent
3rd - we use the limiting reagent to calculate the amount of CO2 in grams
105.7grO2*(264grCO2/240grO2)=116.3 grCO2