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3 years ago

Calculate the amount of heat needed to melt 35.0 g of ice at 0 ºC.Express your answer in kilojoules

2 answers:

6 0

The amount of heat will be equal to Lm.

Where L is the latent heat of fusion and m is mass of the ice.

Latent heat of ice = 80cal/g.

So the amount of heat required here will be 35× 80cal

= 2,800 cal.

Strike441 [17]3 years ago

5 0

That would be 2,800 calories

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3 years ago

Arocket launches at an angle of 33.6 degrees from the horizontal at a

babymother [125]

Answer:

Y component = 32.37

Explanation:

Given:

Angle of projection of the rocket is, $\theta=33.6$

Initial velocity of the rocket is, $u=58.5$

A vector at an angle $\theta$ with the horizontal can be resolved into mutually perpendicular components; one along the horizontal direction and the other along the vertical direction.

If a vector 'A' makes angle $\theta$ with the horizontal, then the horizontal and vertical components are given as:

$A_x=A\cos \theta(\textrm{Horizontal or X component})\\A_y=A\sin \theta(\textrm{Vertical or Y component})$

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$u_y=u\sin \theta$

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$u_y=(58.5)(\sin 33.6)\\u_y=58.5\times 0.55339\\u_y=32.373\approx32.37(\textrm{Rounded to two decimal places})$

Therefore, the Y component of initial velocity is 32.37.

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