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3 years ago

Biologists are keeping track of the different kinds of fish in Lake Michigan. Identify the type of data.

Mathematics

2 answers:

Cerrena [4.2K]3 years ago

7 0

D. Categorical data :)

Ksenya-84 [330]3 years ago

3 0

Answer: D. categorical data

Step-by-step explanation:

There are two main kinds of data a) Quantitative data b) Qualitative data.

Qualitative data is also known as categorical data that do not have any logical order, and it cannot be converted into numerical values.

Given statement : Biologists are keeping track of the different kinds of fish in Lake Michigan.

It means Biologists are keeping track of different categories of fishes.

Hence, It is a type of categorical data.

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If LaTeX: m\angle ABF=8s-6m ∠ A B F = 8 s − 6 and LaTeX: m\angle ABE=2\left(s+11\right)m ∠ A B E = 2 ( s + 11 ), find LaTeX: m\a

kolbaska11 [484]

Answer:

Step-by-step explanation:

Given the angles ∠ABF=8s-6, ∠ABE = 2(s + 11), we are to find the angle ∠EBF. The following expression is true for the three angles;

∠ABF = ∠ABE + ∠EBF

Substituting the given angles into the equation to get the unknown;

8s-6 = 2(s + 11)+ ∠EBF

open the parenthesis

8s-6 = 2s + 22+ ∠EBF

∠EBF = 8s-6-2s-22

collect the like terms

∠EBF = 8s-2s-22-6

∠EBF = 6s-28

factor out the common multiple

∠EBF = 2(3s-14)

<em>Hence the measure of angle ∠EBF is 2(3s-14)</em>

8 0

3 years ago

What is the answer for this question 7(x+4)-7=48-2x

Alex777 [14]

Answer:

x = 3

Step-by-step explanation:

7(x + 4) - 7 = 48 - 2x ← distribute parenthesis and simplify left side

7x + 28 - 7 = 48 - 2x

7x + 21 = 48 - 2x ( add 2x to both sides )

9x + 21 = 48 ( subtract 21 from both sides )

9x = 27 ( divide both sides by 9 )

x = 3

8 0

2 years ago

Read 2 more answers

A chemist examines 12 sedimentary samples for bromide concentraction. The mean bromide concentration for the sample date is 0.43

Umnica [9.8K]

Answer:

a) $z = 1.645$

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$ . This is the critical value, the answer for a).

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015$

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

4 0

3 years ago

Ples help and ples give derect awnser not a link you will get brainly if u do

slamgirl [31]

Im sorry i don’t know this but you should try photomath, it might help!

7 0

3 years ago

In a game of poker a hand of five cards is dealt to each player from a deck of 52 cards. find the probablility of a hand contain

aalyn [17]

Answer:

0.00597

Step-by-step explanation:

Given,

Total number of cards = 52,

In which flush cards = 20,

Also, the number of spade flush cards = 5,

Since,

$\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

Thus, the probability of a hand containing a spade flush, if each player has 5 cards

$=\frac{\text{Ways of selecting a spade flush card}}{\text{Total ways of selecting five cards}}$

$=\frac{^{20}C_5}{^{52}C_5}$

$=\frac{\frac{20!}{5!15!}}{\frac{52!}{5!47!}}$

$=\frac{15504}{2598960}$

= 0.00597

7 0

3 years ago