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aleksley [76]
3 years ago
9

A sprinter travels a distance of 100 m in a time of 11.21 seconds.

Mathematics
2 answers:
sergiy2304 [10]3 years ago
6 0

Answer:

distance travelled by sprinter = 100 m

Time taken = 11.21sec

∵speed = distance/time taken

= 100/9.83

= 10.17 m/s

Now we know, 1 km/h = 1000/3600 m/s

so, 1 m/s = 3600/1000 km/h = 18/5 km/h

∴ 10.17 m/s = 10.17 × 18/5 = 10.17 × 18/5 = 36.612 km/h

Hence, average speed = 36.612 km/h

Step-by-step explanation:

Aleks [24]3 years ago
5 0

Answer:

distance travelled by sprinter = 100 m

Time taken = 11.21sec

Hence, average speed = 36.612 km/h

Step-by-step explanation:

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2 years ago
If A = {w.a, t,c, h, d, 0,8} and U = {a,b,c,d, e, f, g, h, L.), k, l, m, n, o, p, q, r, s, t, u, v, w, x, y, z), find A'
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3 years ago
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3 years ago
F(n) = n² – 3 g(n) = 4n - 1 Find f[g(1)]
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Answer:

f[g(1)]=6.

Explanation:

Given f(n) and g(n) defined below:

\begin{gathered} f\mleft(n\mright)=n^2-3 \\ g\mleft(n\mright)=4n-1 \end{gathered}

First, we evaluate g(1):

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8 0
1 year ago
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