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LenKa [72]
2 years ago
8

The blank and the blank of atoms are the same on both sides of a chemical equation.

Chemistry
1 answer:
tester [92]2 years ago
7 0

Answer:

Every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. Therefore, there must be the same number of atoms of each element on each side of a chemical equation.

Explanation:

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Complete this equation for the dissociation of na2co3(aq). omit water from the equation because it is understood to be present.
Elanso [62]
Note that we are omitting the water.

So, sodium carbonate will basically dissociate into positive sodium ions and negative carbonate ions based on the following equation:
 <span>Na2CO3 → 2 Na(+) + CO3(2-)
</span>
If we took water into consideration:
Sodium carbonate will dissociate in water forming carbonic acid and sodium hydroxide. Since sodium hydroxide is a strong base, therefore, it will then neutralize the gastric acid, thus, acting as an antacid.
7 0
3 years ago
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Calculate and round to the correct number of significant digits .
Marianna [84]

Answer:The solution is in the attached file

Explanation:

5 0
2 years ago
How many particles are in 4g of NaCl? (1mol of NaCl = 58g) – 2 step conversion
oksian1 [2.3K]

Answer:

4.16 * 10²⁴ particles

Explanation:

1. We convert from grams to moles

4 g NaCl / 58 g of NaCl = 0.0689655172 moles

-> 0.0690 moles

2. Now we will convert from moles to particles by multiplying by avogadro's number..

0.0690 * 6.022 *10²³ = 4.15518 * 10²⁴ particles or 4.16 * 10²⁴ particles

4 0
3 years ago
How many moles of boron<br> (B, 10.81 g/mol) are in 37.8<br> grams of boron?<br> [?] moles
madreJ [45]

Answer:

37.8g/ 10.81g/mol = 3.4968...moles

3 0
2 years ago
PLEASE HELP
swat32

Answer:

1461.7 g of AgI

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI

Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:

Mole of AgI = 6.22 moles

Molar mass of AgI = 108 + 127

= 235 g/mol

Mass of AgI =?

Mass = mole × molar mass

Mass of AgI = 6.22 × 235

Mass of AgI = 1461.7 g

Therefore, 1461.7 g of AgI were obtained from the reaction.

5 0
3 years ago
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