Answer:
-1.05 V
Explanation:
A detailed diagram of the setup as required in the question is shown in the image attached to this answer. The electrolytes chosen are SnCl2 for the anode half cell and MnCl2 for the cathode half cell. Tin rod and manganese rod are used as the anode and cathode materials respectively. Electrons flow from anode to cathode as indicated. The battery connected to the set up drives this non spontaneous electrolytic process.
Oxidation half equation;
Sn(s) ------> Sn^2+(aq) + 2e
Reduction half equation:
Mn^2+(aq) + 2e ----> Mn(s)
Cell voltage= E°cathode - E°anode
E°cathode= -1.19V
E°anode= -0.14 V
Cell voltage= -1.19 V - (-0.14V)
Cell voltage= -1.05 V
c.Both the breaking of nuclear bonds and the forming of nuclear bonds.
Explanation:
Nuclear energy is released by the breaking and forming of nuclear bonds. The breaking of nuclear bonds by unstable atoms is known as nuclear fission. The forming of nuclear bonds by combination of light atoms is known as nuclear fusion.
- Nuclear fission is a radioactive decay process in which a heavy nucleus spontaneously disintegrates into lighter ones with the release of energy.
- In nuclear fusion, atomic nuclei combines into larger ones with the release of large amount of energy.
Learn more:
Nuclear decay brainly.com/question/4207569
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<span>Tf is the freezing point of the solution(the solvent plus solute).
T*f is the freezing point of the pure solvent(without solute)
i is the van't Hoff factor.It is approximately the number of particles in solution that are made for each particle of the solute that is placed into solution.Therefore, for nonelectrolytes, i = 1.
Kf is the freezing point depression constant.For water, Kf = 1.86 Degree C/m, or 1.86 Degree C.kg/mol.
Tf is -1.58 Degree C</span>
Answer:
KCl is the answers for the question
Explanation:
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