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Nadya [2.5K]
3 years ago
13

How do is excel interpret data?

Computers and Technology
1 answer:
juin [17]3 years ago
4 0

Explanation:

Once a spreadsheet has a data set stored within its cells, you can process the data. Excel cells can contain functions, formulas and references to other cells that allow you to glean insights in existing data sets, for example by performing calculations on them.

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In the last two decades, how have cameras evolved?
Artist 52 [7]

Answer:

The Changes to Camera Technology over the last 70 years. The technology that the modern camera is based on was created several hundred years ago. ... The company would then reload the camera with new film and send it back to the consumer so they could take more pictures with it.

Explanation:

8 0
3 years ago
Read 2 more answers
The benefit from dividing code into methods known as ________ is gained as follows: After you write code to perform a task once,
Fynjy0 [20]

Answer: B: Divide and Conquer

Explanation:

7 0
3 years ago
Given class triangle (in files triangle.h and triangle.cpp), complete main() to read and set the base and height of triangle1 an
kow [346]

The C++ program that would complete the main () and set the base and height of triangle1 and of triangle2 is:

main.cpp

#include <iostream>

#include "Triangle.h"

using namespace std;

int main()

{

   Triangle Tri1;  

Triangle Tri2;

   double base1, height1, base2, height2;

   cout << "Enter a base for your Triangle1: ";

   cin >> base1;

   cout << "Enter a height for your Triangle1: ";

   cin >> height1;

   cout << endl;

   cout << "Enter a base for your Triangle2: ";

   cin >> base2;

   cout << "Enter a height for your Triangle2: ";

   cin >> height2;

   cout << endl;

   

   cout << "################################" << endl;

   

   cout << "Triangle with larger area:" << endl;

   if ((0.5)*base1*height1 > (0.5)*base2*height2){

      Tri1.setValues(base1, height1);

      Tri1.getValues();

      cout << "Area: " << Tri1.getArea() << endl << endl;

}

else{

 Tri2.setValues(base2, height2);

 Tri2.getValues();

    cout << "Area: " << Tri2.getArea() << endl;

}

   

   return 0;

}

Read more about C++ programs here:

brainly.com/question/20339175

#SPJ1

3 0
1 year ago
What is the foundational domain for business
mr Goodwill [35]

a fundamental domain or fundamental region is a subset of the space which contains exactly one point from each of these orbits . It serves as a geometric realisation for the abstract set of representatives of the orbits . There are many ways to choose a fundamental domain .

hope this help

7 0
2 years ago
A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0
2 years ago
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