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3 years ago

What format are a setups program file in before executed?

Computers and Technology

1 answer:

UkoKoshka [18]3 years ago

6 0

.EXE as they are executable programs. However, it depends on the operating system

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Problem 1: you must write a method for this problem called sentenceAnalyzer Write a program that reads a sentence from the keybo

forsale [732]

Answer:

static void sentenceAnalyzer(String sentence){

int lenOfString = sentence.length()-1;

if(sentence.charAt(lenOfString)=='.'){

System.out.println("Declarative");

}

else if(sentence.charAt(lenOfString)=='?'){

System.out.println("Interrogative");

}

else if(sentence.charAt(lenOfString)=='!'){

System.out.println("Exclamation");

}

else{

System.out.println("Unknown");

}

Explanation:

Using Java programming language

Create the method as required

Obtain the index of the last element using the string length method

Use if and else statements to check if the character at the last index is equal to any of the characters given and print the expected output

see a complete code with the main method below

import java.util.Scanner;

public class num11 {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

//Receiving User input

System.out.println("Enter a sentence");

String sentence = in.nextLine();

// Calling the method

sentenceAnalyzer(sentence);

}

static void sentenceAnalyzer(String sentence){

int lenOfString = sentence.length()-1;

if(sentence.charAt(lenOfString)=='.'){

System.out.println("Declarative");

}

else if(sentence.charAt(lenOfString)=='?'){

System.out.println("Interrogative");

}

else if(sentence.charAt(lenOfString)=='!'){

System.out.println("Exclamation");

}

else{

System.out.println("Unknown");

}

}

8 0

3 years ago

Sabiendo que z1 = 10, z2 = 20, z3 =10 , z4 = 20, n1 = 1200 rpm.

romanna [79]

Answer:

a. engranaje 1 → engranaje 2 → engranaje 3 → engranaje 4

z1 = 10 z2 = 20 z3 =10 z4 = 20

b. n2 = 600 rpm, n3 = 1200 rpm, n4 = 600 rpm

la relacion de transmision = 2

Explanation:

where z1 = 10, z2 = 20, z3 = 10, z4 = 20

and n1 = 1200 rpm

n2 = n1 * z1/z2 = (1200 * 10)/ 20 = 600 rpm

n3 = n2 * z2/z3 = (600 * 20)/ 10 = 1200 rpm

n4 = n3 * z3/z4 = (1200 * 10)/ 20 = 600 rpm

la relacion de transmision = z2/z1 * z3/z2 * z4/z3

= 20/10 * 10/20 * 20/10 = 2 * 0.5 * 2 = 2

7 0

3 years ago

What is the most recognized and widely used database of published nursing practice literature?

faust18 [17]

That would be the Cumalitive Index to Nursing and Allied Health Literature.

7 0

3 years ago

The computer virus is simply a.......... a. diseases b.set of computer instrustruction or code c. types of bacteria

Svetllana [295]

Answer: b

The computer virus is simply a ___

b. Set of computer instructions or code

4 0

2 years ago

What are the benefits of using an ordered list vs. an unordered list? What are the costs?

Rashid [163]

Answer:

The main benefit of the ordered list is that you can apply Binary Search( O( n log n) ) to search the elements. Instead of an unordered list, you need to go through the entire list to do the search( O(n) ).

The main cost of the ordered list is that every time you insert into a sorted list, you need to do comparisons to find where to place the element( O( n log n) ). But, every time you insert into an unsorted, you don't need to find where to place the element in the list ( O(1) ). Another cost for an ordered list is where you need to delete an element, you have an extra cost rearranging the list to maintain the order.

6 0

2 years ago