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3 years ago

Match the following:

Physics

2 answers:

forsale [732]3 years ago

8 0

Answer:

iron metal :chromium

machinery part :nickel or chromium

ornamentation and decoration pieces :silver and gold

processed food :tin coated iron can

bridges and automobiles :zinc metal

distilled water:bad conductor

Explanation:

stellarik [79]3 years ago

3 0

<h3>iron metal :chromium</h3>

machinery part :nickel or chromium

ornamentation and decoration pieces :silver and gold

processed food :tin coated iron can

bridges and automobiles :zinc metal

distilled water:bad conductor

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An electroscope is a device that has small gold foil strips suspended from a metal rod. A student brings a negatively charged ro

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I think it is neutral

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4 years ago

A rubber ball that sits motionless near the edge of a tall bookshelf has no kinetic energy. However, it does have mechanical

klio [65]

It is possible because the rubber ball has mechanical energy which is equal to potential energy.

<h3>What is mechanical energy?</h3>

Mechanical energy of an object is the total energy possessed by the object, including the potential energy and the kinetic energy.

M.A = K.E + P.E

<h3>What is kinetic energy?</h3>

Kinetic energy is the energy possessed by an object due to its motion.

<h3>What is potential energy?</h3>

Potential energy is the energy possessed by an object due to its position.

When kinetic energy (K.E) = 0

M.A = P.E

Thus, it is possible because the rubber ball has mechanical energy which is equal to potential energy.

Learn more about mechanical energy here: brainly.com/question/24443465

8 0

3 years ago

While playing football, Chris runs 4.5 m at 20⁰ south of west. If an opponent was trying to tackle him how far west and south wo

rewona [7]

Answer:

South = 1.5m

West =4.2m

Explanation:

Kindly see attached a rough draft of the situation

Step one

Given data

From the sketch the direction of the player is along the resultant of the triangle, corresponding to the Hypotenuse

Step two:

Hence for an opponent to tackle him towards the south, he must be at

sin θ= opp/hyp

sin 20=x/4.5

x=sin 20*4.5

x=0.342*4.5

x= 1.5m

Also, for an opponent to tackle him towards the south, he must be at

cos θ= adj/hyp

cos 20=y/4.5

y=cos 20*4.5

y=0.93*4.5

y= 4.2m

5 0

3 years ago

A plastic rod has been bent into a circle of radius R = 8.00 cm. It has a charge Q1 = +2.70 pC uniformly distributed along one-q

vovikov84 [41]

Answer:

Part a)

$V = -1.52 V$

Part b)

$V = -1.16 V$

Explanation:

Part a)

Electric potential is a scalar quantity

so here we can say that total potential due to a ring on its center is given as

$V = \frac{kQ}{R}$

here we know that

$Q = Q_1 - 6Q_1$

$Q = - 5 Q_1$

$Q_1 = 2.70 pC$

now we have

$V = \frac{(9\times 10^9)(-5\times 2.70 \times 10^{-12})}{0.08}$

$V = -1.52 V$

Part b)

Potential on the axis of the ring is given as

$V = \frac{kQ}{\sqrt{r^2 + R^2}}$

$V = \frac{(9\times 10^9)(-5\times 2.70\times 10^{-12})}{\sqrt{0.08^2 + 0.0671^2}}$

$V = -1.16 V$

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3 years ago

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8 0

3 years ago

Match the following:​

Match the following: