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2 years ago

Which dot plot matches the tally chart below?

Mathematics

2 answers:

zubka84 [21]2 years ago

5 0

Answer:

(A) my friend

Step-by-step explanation:

please mark Brainliest because the other answer above me is wrong

AveGali [126]2 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

I need help again sorry-

Margaret [11]

Answer:

f(x) = - 2(x - 3)² + 2

Step-by-step explanation:

Given

f(x) = - 2x² + 12x - 16 ( factor out - 2 from the first 2 terms )

= - 2(x² - 6x) - 16

To complete the square

add/subtract ( half the coefficient of the x- term)² to x² - 6x

f(x) = - 2(x² + 2(- 3)x + 9 - 9) - 16

= - 2(x - 3)² + 18 - 16

= - 2(x - 3)² + 2

4 0

3 years ago

You downloaded a video game to your computer. You have a 60-minute free trial of the game. It takes 5 1/6 minutes to set up the

igomit [66]

Answer:

Step-by-step explanation:

Given,

The time for set up the game = $5\frac{1}{6}$ minutes,

Also, the time for each level of game is $7\frac{1}{3\\}$ minutes,

If there are l levels of games,

Then the time taken in all levels of game = $(7\frac{1}{3}) l$ <em> </em>

Hence, the total time ( in minutes ) = Set up time + time in all level

= $5\frac{1}{6} +(7\frac{1}{3}) l$

We have 60-minute of free trial of the game,

So, the total time taken can not be exceed to 60 minutes,

= $5\frac{1}{6} +(7\frac{1}{3}) l\leq 60$

Which is the required inequality.

Option 'B' is correct.

5 0

2 years ago

Jen can bike 12 miles in 40 minutes. How much time will she need to bike 30 miles if her speed remains the same? PLEASE HELP QUI

murzikaleks [220]

Answer: 100 minutes

Step-by-step explanation:

With the given information, we can use a proportion to figure out how long it would take for Jen to bike 30 miles.

$\frac{12mi}{40min} =\frac{30mi}{x} \\$

$12x=30*40$

$12x=1200$

$x=100$

5 0

3 years ago

Read 2 more answers

Its 3 questions plz answer I really need it.

hammer [34]

Answer:

Step-by-step explanation:

6 0

2 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

8 0

3 years ago