Usual s I have no idea sorry
Answer:
−0.75 , 1.25
Explanation:
Please refer to attachment for more information
Answer:
3.50*10^-11 mol3 dm-9
Explanation:
A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25°C. The measured potential difference between the rod and the SHE is 0.5812 V, the rod being positive. Calculate the solubility product constant for silver oxalate.
Ag2C2O4 --> 2Ag+ + C2O4 2-
So Ksp = [Ag+]^2 * [C2O42-]
In 1 L, 2.06*10^-4 mol of silver oxalate dissolve, giving, the same number of mol of oxalate ions, and twice the number of mol (4.12*10^-4) of silver ions.
So Ksp = (4.12*10^-4)^2 * (2.06*10^-4)
= 3.50*10^-11 mol3 dm-9
The simplest way to use the periodic table to identify<span> an </span>element<span> is by looking for the </span>element's<span> name or elemental symbol. The periodic table can be used to </span>identify <span>an </span>element<span> by looking for the </span>element's<span> atomic </span>number<span>. The atomic </span>number of<span> an </span>element<span> is the </span>number of<span> protons found within the atoms of that </span>element<span>.</span>
Answer:
1) mass ZnO = 55.155 g
2) V SO2(g) = 18.289 L
Explanation:
1) Zn + H2O → ZnO + H2
∴ mass Zn = 41.6 g
∴ mm Zn = 65.38 g/mol
⇒ mol Zn = (41.6 g)(mol/61.38 g) = 0.678 mol Zn
⇒ mol ZnO = (0.678 mol Zn)(mol ZnO/mol Zn) = 0.678 mol ZnO
∴ mm ZnO = 81.38 g/mol
⇒ mass ZnO = (0.678 mol ZnO)(81.38 g/mol) = 55.155 g ZnO
2) S(s) + O2(g) → SO2(g)
∴ mass S(s) = 24 g
∴ T = 25°C ≅ 298 K
∴ P = 1 atm
∴ mm S(s) = 32.065 g/mol
⇒ mol S(s) = (24 g)(mol/32.065 g) = 0.7485 mol S(s)
⇒ mol SO2(g) = (0.7485 mol S(s))(mol SO2(g)/mol S(s)) = 0.7485 mol SO2(g)
ideal gas:
⇒ V SO2(g) = ((0.082 atm.L/K.mol)(298 K)(0.7485 mol))/(1 atm)
⇒ V SO2(g) = 18.289 L SO2(g)
