Answer:
0.008945 atm
Explanation:
In the reaction:
2H2S(g) ⇌ 2 H2(g) + S2(g)
Kp is defined as:
<em>Where P is the pressure of each compound in equilibrium.</em>
If initial pressure of H2S is 3.00atm, concentrations in equilibrium are:
H2S = 3.00 atm - 2X
H2 = 2X
S2: = X
Replacing:
0 = 4X³ - 1.28x10⁻⁶X² + 1.92x10⁻⁶X - 2.88x10⁻⁶
Solving for X:
X = 0.008945 atm
As in equilibrium, pressure of S2 is X, <em>pressure is 0.008945 atm</em>
Answer:
The mass percent of carbon in C₁₄H₁₉NO₂ is 72.1%.
Explanation:
To calculate the mass percent of carbon in C₁₄H₁₉NO₂ we have to follow two simple steps:
1st) Look for the atomic weight of each element in the Periodic Table and then multiply each one by its subscript in the molecule and finally sum all of them to find the molar weight of the molecule:
Carbon atomic weight . Carbon subscript = 12 . 14 = 168g
Hydrogen atomic weight . Hydrogen subscript = 1 . 19 = 19g
Nitrogen atomic weight . Nitrogen subscript = 14 . 1 = 14g
Oxygen atomic weight . Oxygen subscript = 16 . 2 = 32g
The molar weight of C₁₄H₁₉NO₂ is: 168g + 19g + 14g +32g = 233g.
2nd) Find the mass percent of carbon with a Rule of three:
If 233g represents the 100% of mass, the 168g of carbon in the molecule will represents the 72.1% of mass.
The Rule of three is:
233g ------------- 100%
168g ------------- = (168 . 100)/233 = 72.1% mass of carbon.
Nitrogen is essential for all living things because it is a major part of amino acid.
So the answer is A
Answer:
CH3—CH2—O—CH2—CH3 is the compound of glycol.
