Answer:
The redshift data does not support the Big Bang Theory and without the redshift interpretation favored by the Big bang, there is no Big Bang.
Edwin Hubble did not believe that the redshift indicated expansion. Hubble saw the redshift as an hitherto unrecognized principle of nature. The redshift is the effect of centripetal force mv2/r = mv2/ct = v/c(mv/t) = v/c(p/t)= (v/c)m
The unrecognized principle of nature is the refraction effect of gravity on light.
n=c/v or v= c/n.
The Universe is older than 13.7 Billion years, likely around 16.5 billion years.
The proper law of Gravity is W = -mGM/r + cmV = -mu/r + cP where cP is the so-called "Dark Energy", or the actual vector Momentum Energy cmV= cP. This is The Quaternion Universe with scalar and vector energy!
Hope this helps!
Answer:
work being done on an object.
Answer. A. A man pushes a couch across the room
diagram identifies an axle:
Answer: B. Z
simple machine described as a shaft at the center of a wheel:
Answer: D. Wheel and axle
Type of lever:
A. a catapult
The force exerted on the box is 56 N
Explanation:
The work done by a force on an object is given by
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
For the box in this problem, we have:
W = 2240 J is the work done
d = 40 m is the displacement of the box
Assuming that the force is parallel to the displacement, 
Solving the equation for F, we find the force exerted on the box:
Learn more about work:
brainly.com/question/6763771
brainly.com/question/6443626
#LearnwithBrainly
what?????????????!!!!!!!!!!!!!!
Answer:
7.55 km/s
Explanation:
The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:
where
is the gravitational constant
is the mass of the telescope
is the mass of the Earth
is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)
v = ? is the orbital velocity of the Hubble telescope
Re-arranging the equation and substituting numbers, we find the orbital velocity:
