Yes.
The acceleration vector WILL point south when the car is slowing down while traveling north
The new velocity after 4 s is 40 m/s
The height of the spaceship above the ground after 5 seconds is 1,127.5 m
The given parameters for the first question;
- initial velocity of the car, u = 76 m/s
- acceleration of the car, a = - 9 m/s²
The new velocity after 4 s is calculated as;
v = u + at
v = 76 + (-9)(4)
v = 76 - 36
v = 40 m/s
(5)
The given parameters;
- height above the ground, h = 500 m
- velocity of spaceship, u = 150 m/s
The height of the spaceship above the ground after 5 seconds is calculated as;

Learn more here: brainly.com/question/24527971
Explanation:
Submultiples Multiples
Value SI symbol Name
10−1 s ds decasecond
10−2 s cs hectosecond
10−3 s ms kilosecond
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