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dezoksy [38]
3 years ago
13

Q is granite, an igneous rock. Which of these is NOT a characteristic of igneous rock?

Physics
2 answers:
fgiga [73]3 years ago
8 0

Igneous rocks are conglomerates, predominantly composed of rounded

gravel

Explanation:

The statement that igneous rocks are conglomerate predominantly composed of rounded gravel is not correct. Igneous rocks are rocks formed from magma that cools and solidifies.

  • Conglomerates are sedimentary rocks that are made of rounded clasts in a matrix.
  • They differ from igneous rocks that crystallize from molten magma.
  • Sedimentary rocks are usually derived from the process of weathering, erosion, transportation and deposition on the earth surface.
  • Igneous rocks forms from crystallized magma which can be on the surface or deep within the crust.

Learn more:

Sedimentary rocks brainly.com/question/2740663

#learnwithBrainly

Inga [223]3 years ago
7 0

Answer:

C.

Explanation:

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The resolving power of electron microscopes is much better than the resolving power of light microscopes because the wavelength
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Answer:

because the wavelength of electron beams is much shorter than the wavelength of visible light

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3 years ago
The distance between two charged objects is doubled. What happens to the electrostatic force between the two?a)It will double.b)
zzz [600]

Answer:

d) It will be cut to a fourth of the original force.

Explanation:

The magnitude of the electrostatic force between the charged objects is

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the separation between the two objects

In this problem, the initial distance is doubled, so

r' = 2r

Therefore, the new electrostatic force will be

F=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(2r)^2}=\frac{1}{4}(k\frac{q_1 q_2}{r^2})=\frac{1}{4}F

So, the force will be cut to 1/4 of the original value.

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3 years ago
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5 0
2 years ago
A hydraulic machine can be used to lift extremely heavy objects. Why is the fluid in the hydraulic machine a liquid rather than
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3 years ago
Read 2 more answers
Suppose the ring rotates once every 4.30 ss . If a rider's mass is 58.0 kgkg , with how much force does the ring push on her at
Stells [14]

Answer:

422.36 N

Explanation:

given,

time of rotation = 4.30 s

T = 4.30 s

Assuming the diameter of the ring equal to 16 m

radius, R = 8 m

v = \dfrac{2\pi R}{T}

v = \dfrac{2\pi\times 8}{4.30}

  v = 11.69 m/s

now, Force does the ring push on her at the top

- N - m g = \dfrac{-mv^2}{R}

N + m g = \dfrac{mv^2}{R}

N = \dfrac{mv^2}{R}- m g

N = m(\dfrac{v^2}{R}- g)

N = 58\times (\dfrac{11.69^2}{8}- 9.8)

N = 422.36 N

The force exerted by the ring to push her is equal to 422.36 N.

6 0
2 years ago
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