an electron and a 0.0320-kg bullet each have a velocity of magnitude 510 m/s, accurate to within 0.0100%. within what lower limi

Question

1 year ago

14

t could we determine the position of each object along the direction of the velocity?electron mmbullet m

1 answer:

MArishka [77] · Answer 1 · 2024-07-04T14:35:22+03:00

for this we apply, Heisenberg's uncertainty principle.

it states that physical variables like position and momentum, can never simultaneously know both variables at the same moment.

the formula is,

Δp * Δx = h/4π

m(e).Δv * Δx = h/4π

by rearranging,

Δx = h / 4π * m(e).Δv

Δx = (6.63*10^-34) / 4 * 3.142 * 9.11*10^-31 * 5.10*10^-2

Δx = 6.63*10^-34 / 583.9 X 10 ⁻³¹

Δx = 0.011 X 10⁻³

for the bullet

Δx = (6.63*10^-34) / 4 * 3.142 * 0.032*10^-31 * 5.10*10^-2

Δx = 6.63*10^-34 /2.05

Δx =3.23 X 10⁻³² m

therefore, we can say that the lower limits are 0.011 X 10⁻³ m for the electron and 3.23 X 10⁻³² m for the bullet

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